重命名r中相同数据框列表中的同一列

Question

我对 R 还很陌生，我想知道是否有人可以帮助我？

我有一个相同数据帧（df1、df2、...、df9）的列表，我正在尝试将所有数据帧中的一列“value”重命名为“value_dataframename”-所有 9 个数据框中的重命名列应为 df1 中的 value_df1、df2 中的 value_df2、...、df9 中的 value_df9。

任何帮助将不胜感激！

Answer 1

试试这个：

## these two are my sample data frames for this example
df_1 <- data.frame(first = rbinom(10,size = 2,prob = 0.3), second = rnorm(10))
df_2 <- data.frame(first = rbinom(10,size = 2,prob = 0.3), second = rnorm(10))

# R stores data frames as list, so you can retrieve all your data frames thus:
all_df_names = ls.str(mode = "list")

# to check: all_df_names[1] - the first element - will give you "df_1", which is the name of the first data frame
# be careful though - 'ls.str(mode = "list")' will pick ALL the lists currently in your environment
# if you don't want to use this ls method, it might be wiser to manually create a variable 'all_df_names' and put all your data frame names there yourself.

# rename
for(i in 1:length(all_df_names)) {
  # get the actual content via its variable name, and store it in a temporary variable 'x'
  x = get(all_df_names[i])
  # rename the column you want
  names(x)[2] = paste0(names(x)[2], "_", i)   # this will replace the column with the previous name plus a '_' and the current iteration
  # resave that dataframe, with the new content
  assign(all_df_names[i], x)
}

# to remove variables we no longer need when done:
# rm(x, i)

# confirm
# names(df_1) = "first"    "second_1"
# names(df_2) = "first"    "second_2"

Answer 2

下面的代码示例列表 (auto.list) 可以满足您的需求。运行它来检查。 要将其用于您的列表：

1. 跳过代码直到your.list <- ...行，
2. 将您的列表保存为your.list 对象，
3. 分配给term你的“价值”。

auto.list <- list()

for (i in seq_len(10)) {
  auto.list[[i]] <- data.frame("a" = 1:i, "value" = sample(letters, i))
  names(auto.list)[i] <- paste0("df", i)
}
    
your.list <- auto.list # assign to your.list your own list
term <- "value" # assign your own "value"
   
for (i in seq_along(your.list)) {
  colnames(your.list[[i]])[colnames(your.list[[i]]) == term] <- paste0(term, "_", names(your.list)[i])
}