【发布时间】:2014-11-26 19:04:44
【问题描述】:
我一定看过一百多篇关于此的帖子,但没有一篇文章足够接近我可以弄清楚这一点。我有两张表——一张“住房”表和一张“汇总”表。我需要计算“房屋”表中的单元数, 1.) 具有“活跃”状态和“出租”类别,并且 2.) 具有“活跃”状态和“销售”类别 ...在几个建筑物中的每一个中,然后在“汇总”表中的建筑物名称旁边插入计数:
‘住房’表
Building Unit No. Status Class
---------- ---------- ------- ------
10 South Hampton 1107 Active Rental
1 Nile Place 712 Active Sale
Forsythe Tower N 203N Closed Sale
Forsythe Tower S 117S Active Rental
Hickory Commons 315 Closed Sale
10 South Hampton 202 Active Sale
1 Nile Place 311 Active Rental
Forsythe Tower N 619N Active Rental
Forsythe Tower N 408N Active Sale
Hickory Commons 202 Closed Sale
10 South Hampton 1420 Closed Rental
1 Nile Place 507 Active Rental
Forsythe Tower N 810N Active Sale
Forsythe Tower S 716S Active Sale
Hickory Commons 319 Active Rental
‘汇总’表
Building Sales Rentals Col3 Col4 Col5
---------- ------ ------- ------ ----- ------
1 Nile Place 1 2
10 South Hampton 1 1
Forsythe Tower N 2 1
Forsythe Tower S 1 1
Hickory Commons 0 1
我得到了一个单一的计数(销售):
REPLACE summary (Building, Sales)
SELECT Building,
COUNT(*) FROM housing WHERE Status='Active' AND class ='Sales',
GROUP BY Building
然后我觉得很危险,发现下面的片段,看起来很棒,但对两者都不起作用
REPLACE summary (Sales, Rentals)
SELECT Building,
SUM(Class ='Sales' AND Status='Active') Sales,
SUM(Class='Rentals' AND Status='Active') Rentals
FROM summary
GROUP BY Building
我真的只是在 mySQL 的这方面沾沾自喜,因此非常感谢有关如何破解它的建议。
谢谢。
【问题讨论】:
标签: mysql replace insert count