在记事本++中的块选择中搜索/替换答案

【问题标题】：Search/replace in block selection in Notepad++在记事本++中的块选择中搜索/替换
【发布时间】：2015-06-27 20:19:49
【问题描述】：

有没有办法将搜索/替换仅限于 Notepad++ 中的柱状块选择？

这是我想要做的：

我正在批量编辑从大量照片中提取的元数据。
元数据以 csv 文件的形式提供给我，标题行中的字段周围没有引号，每个后续行的第一个字段周围也没有引号。
我在 Open Office calc 中编辑此文件，该文件在所有字段周围都带有引号。
我可以轻松编辑标题行，但问题在于仅从连续行的第一个字段中去除引号。
我可以在列模式下使用记事本，但是在选择第一列后，“仅在选择中搜索”选项框显示为灰色。
我可以手工完成，但这意味着大量的手工工作和增加出错的机会。

【问题讨论】：

标签： replace notepad++ block selection

【解决方案1】：

我知道，这可能对你没有任何帮助，但我只是遇到了同样的问题，偶然发现了这个问题。

我发现将有问题的块移动到一个新文件并在那里执行查找/替换工作相当不错。移回方块时，一定要在方块模式下选择它（见this question）。

【讨论】：

【解决方案2】：

没有。其他编辑器可能具有此功能。

【讨论】：

Visual Slickedit 具有此功能和许多其他列选择功能。

【解决方案3】：

回复有点晚，但是...当我搬到安装了 Notepad++ 的新机器上时，我遇到了同样的问题。以前，我使用的是一个名为 Boxer 的文本编辑器，它具有此功能，我发现它非常宝贵。但是它不是免费软件。

【讨论】：

【解决方案4】：

您可能无法在列式选择中搜索/替换，但您可以在 Notepad++ 中轻松执行任务。使用查找和替换功能，正则表达式框选中。

如果您只想从目标列中删除引号，请在查找字段中使用以下正则表达式：

 (^([^,]*,){i})"([^,\n\r]*)"(.*$)

将i替换为目标列的位置减1。

（即 - 如果您想在第三列周围加引号，则为 2，第一列为 0 等）

在替换字段中使用：

 \1\3\4

单击“全部替换”将从目标列中删除引号。

如果您想在不带偏见的情况下删除 csv 中每个元素周围的所有引号，请在 Find 字段中使用以下正则表达式：

 ((?<=,)|(?<=^))"(.*?)"((?=$|,))

在替换字段中使用：

 \1\2\3

点击全部替换将去掉列中的引号。

示例

由于您没有提供示例 csv 文件，我将介绍自己的工作示例。下面是我的 csv：

 "0","1","2","3","4","5","6","7","8","9"
 "10","11","12","13","14","15","16","17","18","19"
 "20","21","22","23","24","25","26","27","28","29"
 "30","31","32","33","34","35","36","37","38","39"
 "40","41","42","43","44","45","46","47","48","49"
 "50","51","52","53","54","55","56","57","58","59"
 "60","61","62","63","64","65","66","67","68","69"
 "70","71","72","73","74","75","76","77","78","79"
 "80","81","82","83","84","85","86","87","88","89"
 "90","91","92","93","94","95","96","97","98","99"
 "100","101","102","103","104","105","106","107","108","109"
 "110","111","112","113","114","115","116","117","118","119"
 "120","121","122","123","124","125","126","127","128","129"
 "130","131","132","133","134","135","136","137","138","139"
 "140","141","142","143","144","145","146","147","148","149"
 "150","151","152","153","154","155","156","157","158","159"
 "160","161","162","163","164","165","166","167","168","169"
 "170","171","172","173","174","175","176","177","178","179"
 "180","181","182","183","184","185","186","187","188","189"
 "190","191","192","193","194","195","196","197","198","199"

如果我想从第二列中删除引号，我会使用下面的 Find 和 Replace 字段

 (^([^,]*,){1})"([^,\n\r]*)"(.*$)

 \1"\3"\4

单击全部替换会产生以下结果：

 "0",1,"2","3","4","5","6","7","8","9"
 "10",11,"12","13","14","15","16","17","18","19"
 "20",21,"22","23","24","25","26","27","28","29"
 "30",31,"32","33","34","35","36","37","38","39"
 "40",41,"42","43","44","45","46","47","48","49"
 "50",51,"52","53","54","55","56","57","58","59"
 "60",61,"62","63","64","65","66","67","68","69"
 "70",71,"72","73","74","75","76","77","78","79"
 "80",81,"82","83","84","85","86","87","88","89"
 "90",91,"92","93","94","95","96","97","98","99"
 "100",101,"102","103","104","105","106","107","108","109"
 "110",111,"112","113","114","115","116","117","118","119"
 "120",121,"122","123","124","125","126","127","128","129"
 "130",131,"132","133","134","135","136","137","138","139"
 "140",141,"142","143","144","145","146","147","148","149"
 "150",151,"152","153","154","155","156","157","158","159"
 "160",161,"162","163","164","165","166","167","168","169"
 "170",171,"172","173","174","175","176","177","178","179"
 "180",181,"182","183","184","185","186","187","188","189"
 "190",191,"192","193","194","195","196","197","198","199"

【讨论】：

【解决方案5】：

我在互联网上的搜索，查看天气记事本++ 支持这一点；带我到这。我使用过 TextPad 并确认它支持在列选定块中查找和替换。 TextPad 也是免费供个人使用的。

【讨论】：