用字符串中的新数组替换旧数组

Question

我有一个 var 包含字符串，并且我有一个包含字符串中单词的数组，称为 oldWords，新数组包含新单词，称为 newWords 我想用字符串中的 newWords 替换 oldWords 我已经尝试使用 for 循环但它返回仅替换最后一个单词的字符串。

代码：

let myStr = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Fusce sapien magna.",
    old_Words = ["Lorem", "ipsum"],
    new_Words = ["word1", "word2"];
    
for (let i = 0; i < old_Words.length; i++) {
  var newStr = myStr.replace(old_Words[i], new_Words[i]);
}

console.log(newStr);

输出应该是：

"word1 word2 dolor sit amet, consectetur adipiscing elit. Fusce sapien magna."

Answer 1

您可以将所有出现的旧词替换为新词，如下所示：

注意： 这也可以替换多次出现的单词。

let myStr = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Lorem ipsum dolor Fusce sapien magna.",
    old_Words = ["Lorem","ipsum"],
    new_Words = ["word1","word2"];
    
old_Words.forEach((oldWord, idx) => {
  myStr = myStr.replace(RegExp(oldWord, 'g'), new_Words[idx])
});

console.log(myStr)

let myStr = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Lorem Fusce ipsum sapien magna.",
    old_Words = ["Lorem","ipsum"],
    new_Words = ["word1","word2"];
    
old_Words.forEach((oldWord, idx) => {
  myStr = myStr.replace(RegExp(oldWord, 'g'), new_Words[idx])
});

console.log(myStr)

Answer 2

在循环前以let newStr = myStr; 开始，然后在循环内执行newStr = newStr.replace(...)：

let myStr = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Fusce sapien magna.",
    old_Words = ["Lorem","ipsum"],
    new_Words = ["word1","word2"],
    newStr = myStr;

for (let i = 0; i < old_Words.length; i++){
  newStr = newStr.replace(old_Words[i], new_Words[i]);
}
console.log(newStr);