Python中，如何根据多个属性值设置替换一个json子对象？

Question

[
{
    "builtin_name": "custom_template",
    "fields": [
        {
            "id": 10012,
            "field_type": "OBJECT_SET",
            "tooltip_text": "",
            "name_plural": "",
            "name_singular": "reference",
            "backref_name": "reference",
            "backref_tooltip_text": "",
            "allow_multiple": false,
            "allowed_otypes": [
                "schema",
                "table",
                "attribute",
                "user",
                "groupprofile",
                "groupprofile"
            ],
            "options": null,
            "builtin_name": null
        },
        {
            "id": 8,
            "field_type": "OBJECT_SET",
            "tooltip_text": null,
            "name_plural": "Stewards",
            "name_singular": "Steward",
            "backref_name": "Steward",
            "backref_tooltip_text": null,
            "allow_multiple": true,
            "allowed_otypes": ["user", "groupprofile", "groupprofile"],
            "options": null,
            "builtin_name": "steward"
        }
    ],
    "id": 16,
    "title": "Custom template"
},
{
    "builtin_name": "new_template",
    "fields": [
        {
            "id": 10011,
            "field_type": "PICKER",
            "tooltip_text": "",
            "name_plural": "",
            "name_singular": "status",
            "backref_name": "",
            "backref_tooltip_text": "",
            "allow_multiple": false,
            "allowed_otypes": null,
            "options": [
                {
                    "old_index": 0,
                    "article_id": null,
                    "tooltip_text": null,
                    "in_use": true,
                    "title": "Done"
                }
            ],
            "builtin_name": null
        }
    ],
    "id": 1899,
    "title": "New Template"
}

] 使用这个 JSON 对象，我想替换 fields 列表，其中 id=16 and title=Custom template。我已经生成了要用于替换的对象。

这是我尝试过的，但没有奏效：

i=0    
jdata_copy = jdata #this is so I can compare
for t in jdata:
    if(t["title"]=="Custom template" and t["id"]==16):            
        jdata_copy[i]["fields"] = repl_data
    i+=1 

我四处寻找一个简单的 json 替换，但没有找到。

感谢一些帮助。

谢谢！

Answer 1

好的，假设 python 脚本与名为 test.json 的 json 文件位于同一目录中，这就是 json 的样子（与您的不一样，因为您的具有 null 和 None 值某种原因，所以我不知道该怎么办）：

[
    {
        "builtin_name": "custom_template",
        "fields": [
            {
                "id": 10012,
                "field_type": "OBJECT_SET",
                "tooltip_text": "",
                "name_plural": "",
                "name_singular": "reference",
                "backref_name": "reference",
                "backref_tooltip_text": "",
                "allow_multiple": false,
                "allowed_otypes": [
                    "schema",
                    "table",
                    "attribute",
                    "user",
                    "groupprofile",
                    "groupprofile"
                ],
                "options": null,
                "builtin_name": null
            },
            {
                "id": 8,
                "field_type": "OBJECT_SET",
                "tooltip_text": null,
                "name_plural": "Stewards",
                "name_singular": "Steward",
                "backref_name": "Steward",
                "backref_tooltip_text": null,
                "allow_multiple": true,
                "allowed_otypes": ["user", "groupprofile", "groupprofile"],
                "options": null,
                "builtin_name": "steward"
            }
        ],
        "id": 16,
        "title": "Custom template"
    },
    {
        "builtin_name": "new_template",
        "fields": [
            {
                "id": 10011,
                "field_type": "PICKER",
                "tooltip_text": "",
                "name_plural": "",
                "name_singular": "status",
                "backref_name": "",
                "backref_tooltip_text": "",
                "allow_multiple": false,
                "allowed_otypes": null,
                "options": [
                    {
                        "old_index": 0,
                        "article_id": null,
                        "tooltip_text": null,
                        "in_use": true,
                        "title": "Done"
                    }
                ],
                "builtin_name": null
            }
        ],
        "id": 1899,
        "title": "New Template"
    }
]

然后，这段代码可以加载和更改fields：

import json


with open("test.json") as json_file:
    jdata = json.load(json_file)

jdata_copy = jdata

对于 jdata 中的 t： 如果 t["id"] == 16 和 t["title"] == "自定义模板"： pprint(jdata) 打印（） t[“字段”] = [“你好”，“你好”] 打印（） pprint(jdata)

但是，如果您是这种情况，请告诉我，我不确定您的问题到底是什么。

编辑

因此，将代码更改为：

import json
from pprint import pprint


with open("test.json") as json_file:
    jdata = json.load(json_file)

jdata_copy = jdata

for t in jdata:
    if t["id"] == 16 and t["title"] == "Custom template":
        pprint(jdata)

        t["fields"] = ["howdy", "hello"]

        pprint(jdata)

有了这个，我可以看到第一个 print 语句将 json 作为一个 python 字典返回，第二个 print 语句确实显示 jdata 已经修改了正确字典的fields 部分。

然后，我可以将字典导出回.json：

with open("test1.json", "w") as json_file:
    json.dump(jdata, json_file)

这一切对我来说都很好，这里的哪个部分不适合你？对不起，如果我误解了。