如何在字符串中搜索特定字符并替换它们？ [复制]

Question

嘿，我知道这是一个愚蠢的问题，但我真的需要在我的编程课上完成一个练习，而我在任何地方都找不到解决方案。

基本上我需要在“tweet”中搜索诸如 lol 之类的缩写词，然后用实际单词替换它们。

我试过这段代码，但它有时会删除字符串的开头。

string usertweet;
cout << "Please enter a tweet. " << endl; 
cin >> usertweet;

getline(cin, usertweet);
usertweet.resize(160); // Cut down the tweet to 160 chars.

int position; //Used for searching for abrvs.
position = usertweet.find("AFK");
if (position >= 0) {
    usertweet.replace(position,3,"Away from Keyboard");
}

position = usertweet.find("BRB");
if (position >= 0) {
    usertweet.replace(position,3,"Be Right Back");
}

cout << usertweet;

抱歉这个愚蠢的问题，提前非常感谢您！

Answer 1

改成

string usertweet;
cout << "Please enter a tweet. " << endl; 
cin >> usertweet;

getline(cin, usertweet);
usertweet.resize(160); // Cut down the tweet to 160 chars.

for (size_t p = usertweet.find("AFK"); p != string::npos; p = usertweet.find("AFK", p + 1))
    usertweet.replace(p, 3, "Away from Keyboard");

for (size_t p = usertweet.find("BRB"); p != string::npos; p = usertweet.find("BRB", p + 1))
    usertweet.replace(p, 3, "Be Right Back");

cout << usertweet;