【发布时间】:2019-01-08 06:13:29
【问题描述】:
如何在 spark 数据帧中转换结构数组?
让我通过一个例子来解释我想要做什么。 我们将首先创建一个包含行数组和嵌套行的数据框。我的整数尚未在数据框中转换,它们被创建为字符串:
import org.apache.spark.sql._
import org.apache.spark.sql.types._
val rows1 = Seq(
Row("1", Row("a", "b"), "8.00", Seq(Row("1","2"), Row("12","22"))),
Row("2", Row("c", "d"), "9.00", Seq(Row("3","4"), Row("33","44")))
)
val rows1Rdd = spark.sparkContext.parallelize(rows1, 4)
val schema1 = StructType(
Seq(
StructField("id", StringType, true),
StructField("s1", StructType(
Seq(
StructField("x", StringType, true),
StructField("y", StringType, true)
)
), true),
StructField("d", StringType, true),
StructField("s2", ArrayType(StructType(
Seq(
StructField("u", StringType, true),
StructField("v", StringType, true)
)
)), true)
)
)
val df1 = spark.createDataFrame(rows1Rdd, schema1)
这是创建的数据框的架构:
df1.printSchema
root
|-- id: string (nullable = true)
|-- s1: struct (nullable = true)
| |-- x: string (nullable = true)
| |-- y: string (nullable = true)
|-- d: string (nullable = true)
|-- s2: array (nullable = true)
| |-- element: struct (containsNull = true)
| | |-- u: string (nullable = true)
| | |-- v: string (nullable = true)
我想要做的是将所有可以是整数的字符串转换为整数。我尝试执行以下操作,但没有成功:
df1.selectExpr("CAST (id AS INTEGER) as id",
"STRUCT (s1.x, s1.y) AS s1",
"CAST (d AS DECIMAL) as d",
"Array (Struct(CAST (s2.u AS INTEGER), CAST (s2.v AS INTEGER))) as s2").show()
我遇到了以下异常:
cannot resolve 'CAST(`s2`.`u` AS INT)' due to data type mismatch: cannot cast array<string> to int; line 1 pos 14;
任何人都有正确的查询将所有值转换为 INTEGER 吗?我将不胜感激。
非常感谢,
【问题讨论】:
标签: sql scala apache-spark dataframe apache-spark-sql