您说您的用户数据框很大,并且“geohashes 可能会在 idvalue 内部和跨 idvalue 重复”。但是,如果您的商店数据框中可能存在重复的地理哈希,您没有提及。
如果后者没有重复的哈希,我认为一个简单的连接可以解决你的问题:
val userDf = Seq(("id-1",2,"gcutjjn"),("id-2",2,"gcutjjn"),("id-1",3,"gcutjjn"),("id-1",5,"gcutjht")).toDF("idvalue","day_of_week","geohash")
val shopDf = Seq(("sid-1","kfc","gcutjjn"),("sid-2","mcd","gcutjhq"),("sid-3","starbucks","gcutjht")).toDF("shop_id","shop_name","geohash")
userDf.show
+-------+-----------+-------+
|idvalue|day_of_week|geohash|
+-------+-----------+-------+
| id-1| 2|gcutjjn|
| id-2| 2|gcutjjn|
| id-1| 3|gcutjjn|
| id-1| 5|gcutjht|
+-------+-----------+-------+
shopDf.show
+-------+---------+-------+
|shop_id|shop_name|geohash|
+-------+---------+-------+
| sid-1| kfc|gcutjjn|
| sid-2| mcd|gcutjhq|
| sid-3|starbucks|gcutjht|
+-------+---------+-------+
shopDf
.join(userDf,Seq("geohash"),"inner")
.groupBy($"geohash",$"shop_id",$"idvalue")
.agg(collect_list($"day_of_week").alias("days"))
.show
+-------+-------+-------+------+
|geohash|shop_id|idvalue| days|
+-------+-------+-------+------+
|gcutjjn| sid-1| id-1|[2, 3]|
|gcutjht| sid-3| id-1| [5]|
|gcutjjn| sid-1| id-2| [2]|
+-------+-------+-------+------+
如果您的商店数据框中有重复的哈希值,一种可能的方法是从您的商店数据框中删除这些重复的哈希值(如果您的要求允许的话),然后执行相同的连接操作。
val userDf = Seq(("id-1",2,"gcutjjn"),("id-2",2,"gcutjjn"),("id-1",3,"gcutjjn"),("id-1",5,"gcutjht")).toDF("idvalue","day_of_week","geohash")
val shopDf = Seq(("sid-1","kfc","gcutjjn"),("sid-2","mcd","gcutjhq"),("sid-3","starbucks","gcutjht"),("sid-4","burguer king","gcutjjn")).toDF("shop_id","shop_name","geohash")
userDf.show
+-------+-----------+-------+
|idvalue|day_of_week|geohash|
+-------+-----------+-------+
| id-1| 2|gcutjjn|
| id-2| 2|gcutjjn|
| id-1| 3|gcutjjn|
| id-1| 5|gcutjht|
+-------+-----------+-------+
shopDf.show
+-------+------------+-------+
|shop_id| shop_name|geohash|
+-------+------------+-------+
| sid-1| kfc|gcutjjn| << Duplicated geohash
| sid-2| mcd|gcutjhq|
| sid-3| starbucks|gcutjht|
| sid-4|burguer king|gcutjjn| << Duplicated geohash
+-------+------------+-------+
//Dataframe with hashes to exclude:
val excludedHashes = shopDf.groupBy("geohash").count.filter("count > 1")
excludedHashes.show
+-------+-----+
|geohash|count|
+-------+-----+
|gcutjjn| 2|
+-------+-----+
//Create a dataframe of shops without the ones with duplicated hashes
val cleanShopDf = shopDf.join(excludedHashes,Seq("geohash"),"left_anti")
cleanShopDf.show
+-------+-------+---------+
|geohash|shop_id|shop_name|
+-------+-------+---------+
|gcutjhq| sid-2| mcd|
|gcutjht| sid-3|starbucks|
+-------+-------+---------+
//Perform the same join operation
cleanShopDf.join(userDf,Seq("geohash"),"inner")
.groupBy($"geohash",$"shop_id",$"idvalue")
.agg(collect_list($"day_of_week").alias("days"))
.show
+-------+-------+-------+----+
|geohash|shop_id|idvalue|days|
+-------+-------+-------+----+
|gcutjht| sid-3| id-1| [5]|
+-------+-------+-------+----+
提供的代码是用 Scala 编写的,但可以轻松转换为 Python。
希望这会有所帮助!