无法在 matplotlib 中获取镜头数据的散点图

Question

相信，你做得很好！！我正在尝试绘制昨天利物浦对阵西汉姆联的所有射门（我已经抓取并清理了数据）。我正在使用 matplotlib 绘制散点图，显示利物浦球员的所有尝试。我没有收到任何错误，但看不到结果，即未绘制散点图。以下是我尝试过的代码：

    import pandas as pd
import matplotlib.pyplot as plt
import matplotlib as mpl
from mplsoccer.pitch import Pitch

df_new = pd.read_csv('xyz.csv')

df_new.head(5)

data =  df_new.loc[:, ~df_new.columns.str.contains('^Unnamed')]

data.head(5)

#set general use colors
text_color = 'w'

fig, ax =plt.subplots(figsize=(13,8.5))
fig.set_facecolor('#22312b')
ax.patch.set_facecolor('#22312b')

pitch = Pitch(pitch_type='statsbomb', orientation='vertical',
             pitch_color='#22312b', line_color='#c7d5cc', figsize=(16,11),
             constrained_layout=True, tight_layout=False, view='half')
pitch.draw(ax=ax)

plt.scatter(data['x'],data['y'])

我还附上了包含所有列的数据框的屏幕截图。我的 'x' 和 'y' 已经是浮动的，而不是字符串。谁能帮我得到散点图？提前致谢。

Answer 1

如果你试试这个会怎样：

from mplsoccer.pitch import Pitch
import matplotlib.pyplot as plt
plt.style.use('ggplot')
import pandas as pd

data = pd.read_csv("Book1.csv")
pitch = Pitch(pitch_type='statsbomb', orientation='vertical',
             pitch_color='#22312b', line_color='#c7d5cc', figsize=(16,11),
             constrained_layout=True, tight_layout=False, view='half')
fig, ax = pitch.draw()
sc = pitch.scatter(100*data["x"], 100*data["y"],
                   s=200, label='scatter', ax=ax)