【发布时间】:2015-03-07 08:00:43
【问题描述】:
我在 angularjs 的前端有一个星级指令,我可以将评分保存到评分集合中。 这是我的评级模式/模型:
var mongoose = require('mongoose');
module.exports = mongoose.model('Rating', {
bourbonId: {type: mongoose.Schema.ObjectId, ref: 'Bourbon'},
userId: {type: mongoose.Schema.ObjectId, ref: 'User'},
rating: {type: Number, required: true},
ratingId : {type: mongoose.Schema.ObjectId}
});
这是我需要平均评分的项目:
'use strict';
var mongoose = require('mongoose'),
BourbonSchema = null;
module.exports = mongoose.model('Bourbon', {
BourbonId: {type: mongoose.Schema.ObjectId},
name: {type: String, required: true},
blog: {type: String, required: true},
photo: {type: String, required: true},
ratings: {type: mongoose.Schema.ObjectId, ref: 'Rating'},
rating: {type: Number}
});
var Bourbon = mongoose.model('Bourbon', BourbonSchema);
module.exports = Bourbon;
我需要找到一种通过波旁 ID 匹配的方法。从堆栈溢出来看,似乎使用聚合函数可能是要走的路。 stack overflow link
这是我的控制器中当前损坏的代码。我知道这很遥远,以及我使用 async.map 尝试解决这个问题的失败尝试:
'use strict';
var Bourbon = require('../../../models/bourbon'),
Rating = require('../../../models/rating');
//async = require('async');
module.exports = {
description: 'Get Bourbons',
notes: 'Get Bourbons',
tags:['bourbons'],
handler: function(request, reply){
Bourbon.find(function(err, bourbons){
Bourbon.findOne(id, 'Rating', function(err, bourbon){
Rating.aggregate([
{$match: {bourbonId: {$in: bourbon.ratings}}},
{$group: {bourbonId: bourbon._id, average: {$avg: '$rating'}}}
], function(err, result){
bourbon.rating = result;
reply({bourbons:bourbons});
console.log('Bourbs', bourbons);
});
});
});
}
};
任何帮助将不胜感激。把我的头撞在砖墙上,现在只是把随机代码扔出去。 ..
这是我已经实现的: 型号:
'use strict';
var mongoose = require('mongoose'),
BourbonResultSchema = null;
module.exports = mongoose.model('BourbonResult', {
_Id: {type: mongoose.Schema.ObjectId, 'ref': 'Bourbon'},
avgRating: {type: Number}
});
var BourbonResult = mongoose.model('BourbonResult', BourbonResultSchema, null);
module.exports = BourbonResult;
控制器:
'use strict';
var Bourbon = require('../../../models/bourbon'),
Rating = require('../../../models/rating'),
BourbonResult = require('../../../models/bourbonResult');
//async = require('async');
module.exports = {
description: 'Get Bourbons',
notes: 'Get Bourbons',
tags:['bourbons'],
handler: function(request, reply){
Rating.aggregate(
[
{'$group':{
'_id': '$bourbonId',
'avgRating': {'$avg': '$rating'}
}}
],
function(err,bourbons){
// Map plain results to mongoose document objects
bourbons = bourbons.map(function(result){
return new BourbonResult(result);
});
Bourbon.populate(bourbons,{'path': '_id'},function(err,bourbons){
reply({bourbons:bourbons});
console.log('BourbsRESSSSSS', JSON.stringify(bourbons, undefined, 2));
});
}
);
}
};
这是我从控制台日志返回的内容:
BourbsRESSSSSS [ { _id:
{ _id: 54acf382894ee2bcdebbc7f5,
name: 'example2',
photo: 'http://aries-wineny.com/wp-content/uploads/2014/09/woodford-reserve.jpg',
blog: 'example2',
__v: 0 },
avgRating: 3.3333333333333335 },
{ _id:
{ _id: 54a77e0fe63c850000f1269c,
name: 'example',
photo: 'http://aries-wineny.com/wp-content/uploads/2014/09/woodford-reserve.jpg',
blog: 'example',
__v: 0 },
avgRating: 3 } ]
================================================ ==========================
完美!
【问题讨论】:
-
这个解决方案看起来很酷!但我最终要做的是每次有人给你打分时计算新的平均值并将其存储在原始模型中。
标签: node.js mongodb mongoose mongodb-query aggregation-framework