【发布时间】:2021-01-07 10:45:20
【问题描述】:
大家早上好,
今天我遇到了猫鼬查询。
假设我们有以下集合:
[
{letter: "A", name: "Books", action: "read"},
{letter: "B", name: "Notebook", action: "write"},
{letter: "C", name: "Camera", action: "take photos"},
{letter: "D", name: "Pencil", action: "draw"}
]
我想获得一个子集合,其中包含名称:“Books”和名称:“Pencil”的文档。
期望的输出:
[
{letter: "A", name: "Books", action: "read"},
{letter: "D", name: "Pencil", action: "draw"}
]
是否可以使用“find()”方法?
【问题讨论】:
标签: javascript mongodb express mongoose mongodb-query