Laravel：将结果与 UnionAll 与计数相结合答案

【问题标题】：Laravel: Combining the results with UnionAll with countLaravel：将结果与 UnionAll 与计数相结合
【发布时间】：2017-10-19 22:58:05
【问题描述】：

假设我在表 resume_profiles 中有 2 列

   current_location      city
    | Chennai  |    | Kolkatta   |
    | Mumbai   |    | Ahmaedabad |
    | Pune     |    | Kolkatta   |
    | Kolkatta |    | Pune       |

我需要将这些结果组合成一个 SET，所以我有这样的东西：

   City        Aggregate
| Chennai    |    | 1 |
| Mumbai     |    | 1 |
| Pune       |    | 2 |
| Kolkatta   |    | 3 |
| Ahmaedabad |    | 1 |

查询：

$current_locations = ResumeProfile::selectRaw('current_location as city');

ResumeProfile::selectRaw('city,count(*) as aggregate')
           ->unionAll($current_locations)
           ->groupBy('city')->get();

当我使用上述查询时，我得到以下查询，但有异常

SQLSTATE[21000]：基数违规：1222 使用的 SELECT 语句具有不同的列数（SQL: (select city,count(*) as aggregate from resume_profiles group by city) union all （从resume_profiles中选择current_location作为城市））

我不知道如何实现这一点

【问题讨论】：

标签： mysql laravel laravel-5

【解决方案1】：

尝试这样做：

  $current_locations = ResumeProfile::selectRaw('current_location as city');

 $subquery=ResumeProfile::selectRaw('city')
       ->unionAll($current_locations);

   DB::table(DB::raw("({$subquery->toSql()}) AS s"))
         ->selectRaw('s.city,count(*) as aggregate')
          ->groupBy('s.city')->get();

【讨论】：

【解决方案2】：

你需要的是这样的查询

SELECT city, COUNT(*) aggregate
  FROM (
    SELECT current_location AS city FROM resume_profiles
    UNION ALL
    SELECT city FROM resume_profiles
  ) q
 GROUP BY city

这里是dbfiddle

我没有看到使用 Eloquent 或 QueryBuilder 表达这一点的优雅方式。只需使用原始查询

$sql = <<<'SQL'
SELECT city, COUNT(*) aggregate
  FROM (
    SELECT current_location AS city FROM resume_profiles
    UNION ALL
    SELECT city FROM resume_profiles
  )
 GROUP BY city
SQL;

$cities = DB::select($sql);

修补它：

>>> DB::select($sql); => [ {#706 +"city": "艾哈迈达巴德", +“聚合”：1， }, {#707 +“城市”：“钦奈”， +“聚合”：1， }, {#685 +“城市”：“加尔各答”， +“聚合”：3， }, {#684 +“城市”：“孟买”， +“聚合”：1， }, {#687 +“城市”：“浦那”， +“聚合”：2， }, ]

【讨论】：

【解决方案3】：

我刚刚对此进行了测试，它可以根据您的需要工作。

$cityInfo = DB::table(DB::raw('(select current_location as city from resume_profiles union all select city from resume_profiles) as resume_profiles'))
    ->select(DB::raw('city, count(city) as total'))
    ->groupBy('city')
    ->get();

【讨论】：