如何使用 cakephp 在分页中使用 Where 条件

Question

这里我使用了三个类别。我想在使用分页时从特定类别中获取数据。

我的代码：

public function index( $category_id = null )
{
    if (!$this->KnowledgeSolution->KnowledgeCategory->exists( $category_id ))
    {
        throw new NotFoundException(__('Invalid Knowledge Category'));
    }
    $KnowledgeCategory = $this->KnowledgeSolution->KnowledgeCategory->read(null,$category_id);
    $this->set('KnowledgeCategory', $KnowledgeCategory);

    $this->Paginator->settings['contain'] = array('Users', 'KnowledgeReply'=>array('Users') );
    $this->set('KnowledgeSolutions', $this->Paginator->paginate());    
    /* 
        $this->paginate = array('conditions' => array('Product .title LIKE' => 'a%'),'limit' => 10 );
        $data = $this->paginate('Product');
    */

}

Answer 1

使用下面的

public function index( $category_id = null )
{
    if (!$this->KnowledgeSolution->KnowledgeCategory->exists( $category_id ))
    {
        throw new NotFoundException(__('Invalid Knowledge Category'));
    }
    $KnowledgeCategory = $this->KnowledgeSolution->KnowledgeCategory->read(null,$category_id);
    $this->set('KnowledgeCategory',$KnowledgeCategory);

    $this->Paginator->settings['contain'] = array('Users','KnowledgeReply'=>array('Users') );
    $this->set('KnowledgeSolutions', $this->Paginator->paginate());    

    $this->Paginator->settings = array('conditions' => array('Product .title LIKE' => 'a%'),'limit' => 10 );

    $data = $this->Paginator->paginate('Product');
    $this->set(compact('data'));
}