从过滤对象数组中删除具有特定键值的对象

Question

我有一个对象数组并对其进行过滤：

const test = [
  {
    "id":2,
    "category_id":1,
    "features":["blah","blah","blah","blah"],
    "options":
    {
      "option1":
        {
          "b":22,"c":105,"d":70,"e":345
        },
      "option2":
        {
          "c":25,"c":41,"d":70,"e":345
        }
    }
  },
  {
    "id":4,
    "category_id":2,
    "features":["blah","blah","blah","blah"],
    "options":
    {
      "option1":
        {
          "b":22,"c":105,"d":70,"e":345
        },
      "option2":
        {
          "c":25,"c":41,"d":70,"e":345
        }
    }
  },
  {
    "id":7,
    "category_id":4,
    "features":null,
    "options":null
  },
  {
    "id":11,
    "category_id":6,
    "features":["blah","blah","blah","blah"],
    "options":
    {
      "option1":
        {
          "b":22,"c":105,"d":70,"e":345
        },
      "option2":
        {
          "c":25,"c":41,"d":70,"e":345
        }
    }
  }
]


const filtered = test.filter((t) => {


})

具有“category_id: 4”的对象没有“选项”，但在 filter 内我需要所有存在的选项值：

const filtered = test.filter((t) => {
  const tOptions = Object.values(t.options)

})

它给了我一个错误，因为某些选项不存在。 我知道如何修改数组并删除没有选项的对象（使用 Lodash）

_.reject(test, function(el) { return el.category_id === 4 })

但由于后面的逻辑，我无法修改“测试”数组。 不知何故，我需要这个结果而不接触数组本身：

[
 Object 
 {
  b:22,
  c:105,
  d:70,
  e:345
 }, 
Object 
 {
  c:41,
  d: 70,
  e: 345
 }
]

我真的放弃了。请帮忙。

Answer 1

也许你可以尝试复制对象测试使用 (.. 你的对象) 或 array.splice(index, number of elements, element, element) 或 slice() 祝你好运

Answer 2

添加一个 if 条件来检查 t.options 是否不为空

const filtered = test.filter((t) => {
  if(t.options) { // null and undefined are falsey
     const tOptions = Object.values(t.options);

  } else {
      return false;
  }
});
``