【发布时间】:2019-09-21 16:42:54
【问题描述】:
我有一个像这样的 gRPC API 定义(来自 Akka 文档示例),但要长得多(4000 行只是 service 部分)。
service GreeterService {
rpc SayHello (HelloRequest) returns (HelloReply) {}
rpc ItKeepsTalking (stream HelloRequest) returns (HelloReply) {}
rpc ItKeepsReplying (HelloRequest) returns (stream HelloReply) {}
rpc StreamHellos (stream HelloRequest) returns (stream HelloReply) {}
}
但是,RPC 列表现在变得太长了,我想以某种方式将其“分解”为多个文件,因此该文件更具可读性。像这样的
// file 1:
service GreeterServicePartA {
rpc SayHello (HelloRequest) returns (HelloReply) {}
rpc ItKeepsTalking (stream HelloRequest) returns (HelloReply) {}
}
// file 2:
service GreeterServicePartB {
rpc ItKeepsReplying (HelloRequest) returns (stream HelloReply) {}
rpc StreamHellos (stream HelloRequest) returns (stream HelloReply) {}
}
// main proto file:
import "file1"
import "file2"
service GreeterService = GreeterServicePartA + GreeterServicePartB
即使只是在不同的文件中分别定义 RPC,然后编写这样的内容也会对我有所帮助:
service GreeterService {
rpc SayHello = importedSayHello
rpc ItKeepsTalking = importedKeepsTalking
rpc ItKeepsReplying = importedKeepsReplying
rpc StreamHellos = importedStreamHellos
}
是否可以像这样在 gRPC 原型定义中“组合”服务?
【问题讨论】:
标签: protocol-buffers grpc