【发布时间】:2022-01-05 06:59:14
【问题描述】:
目前,三个不同的存储库需要作为一个事务处理。
我的服务代码是这样写的。但与我想的不同,每个存储库都在生成自己的事务。我该如何解决这个问题?
// TrimService
@Injectable()
export class TrimService {
constructor(
private readonly trimRepository: TrimRepository,
private readonly tireRepository: TireRepository,
private readonly userRepository: UserRepository
) {}
async saveUserTrim(saveUserTrimDto: SaveUserTrimDto, res) {
const queryRunner = await getConnection().createQueryRunner();
await queryRunner.startTransaction();
try {
const findUser: User = await this.userRepository.findUser(
saveUserTrimDto.id,
queryRunner.manager
);
const createTrim: Trim = await this.trimRepository.saveUserTrim(
findUser,
saveUserTrimDto.trimId,
queryRunner.manager
);
await this.tireRepository.saveTrimTire(
createTrim,
res,
queryRunner.manager
);
await queryRunner.commitTransaction();
return createTrim;
} catch (err) {
console.log(err);
await queryRunner.rollbackTransaction();
} finally {
await queryRunner.release();
}
}
}
// userRepository
@EntityRepository(User)
export class UserRepository extends Repository<User> {
async findUser(
id: string,
@TransactionManager() transactionManager?: EntityManager
) {
const findUser = await this.findOne({ id: id });
if (!findUser) {
throw new NotFoundUserException();
}
return findUser;
}
}
【问题讨论】: