引发异常时，kazoo DataWatch 不会退出程序答案

【问题标题】：kazoo DataWatch does not exit the program when exception is raised引发异常时，kazoo DataWatch 不会退出程序
【发布时间】：2018-05-04 23:49:16
【问题描述】：

我使用的是 kazoo=2.2.1、python 2.7、zookeeper 3.4.5--1。我已经设置了一个 DataWatch，如果回调引发异常，我想中止程序。我无法使用以下代码中止

from kazoo.recipe.watchers import DataWatch
from utils.zookeeper import Zookeeper
import time
import sys


def do_stuff(data, stat):
   raise NotImplementedError("abort")


def wrap_do_stuff(data, stat):
    try:
        do_stuff(data, stat)
    except Exception as e:
        if data != '':
            print e.message

            # This does not exit the program
            # sys.exit(-1)

            # This does not exit the program
            # raise e

            # This does not exit the program, just stop the watcher
            return False


def start():
    zookeeper_client = Zookeeper.init_from_config().client
    # Someone is writing into this node after creation
    new_node_path = zookeeper_client.create('/test/',
                                        ephemeral=True, sequence=True)
    path_to_watch = new_node_path
    print path_to_watch
    datawatcher = DataWatch(zookeeper_client, path_to_watch, wrap_do_stuff)

    while True:
        time.sleep(2)
        print "still alive"


if __name__ == '__main__':
    start()

如何中止wrap_do_stuff()？

【问题讨论】：

标签： python apache-zookeeper kazoo

【解决方案1】：

DataWatch 在单独的线程中运行，有特定的方法可以从线程中杀死主进程，请参阅Why does sys.exit() not exit when called inside a thread in Python?

os._exit() 之类的东西确实有效。

【讨论】：