【发布时间】:2015-12-10 12:08:19
【问题描述】:
我有一个消息总线类,它使用 Rx 在 WPF 应用程序中推送多个线程事件。 我的问题 ObserveOnDispatcher 没有在 UI 线程中调用事件处理程序。
代码:
private void button_Click(object sender, RoutedEventArgs e)
{
var messageBus = new MessageBus();
messageBus.GetMessages<Message>().ObserveOnDispatcher().Subscribe(x => TestHanlder(x));
Trace.WriteLine("Main Thread Id:" + Thread.CurrentThread.ManagedThreadId);
var deviceManager = new DeviceManager(messageBus);
deviceManager.Start();
}
private void TestHanlder(Message message)
{
Trace.WriteLine("UI Handler ThreadId:" + Thread.CurrentThread.ManagedThreadId);
}
public class DeviceManager
{
private readonly MessageBus _messageBus;
public DeviceManager(MessageBus messageBus)
{
_messageBus = messageBus;
}
public void Start()
{
for (;;)
{
var t = Task.Factory.StartNew(() => BackGroundTask(), TaskCreationOptions.LongRunning);
t.Wait();
}
}
private void BackGroundTask()
{
Thread.Sleep(1000);
Trace.WriteLine("Push ThreadId:" + Thread.CurrentThread.ManagedThreadId);
var message = new Message();
_messageBus.Publish(message);
}
}
public class MessageBus
{
readonly ISubject<object> _messages;
public MessageBus()
{
_messages = new Subject<object>();
}
public void Publish<TMessage>(TMessage message)
{
_messages.OnNext(message);
}
public IObservable<TMessage> GetMessages<TMessage>()
{
return _messages.OfType<TMessage>();
}
}
public class Message
{
public Message()
{
}
}
Without ObserveOnDispatcher:
messageBus.GetMessages<Message>().Subscribe(x => TestHanlder(x));
..........................Output.................................
Main Thread Id:8
Push ThreadId:9
UI Handler ThreadId:9
But I need to execute the TestHanlder function in the main thread or UI thread, in my use case above it must be the thread number 8.
When I use ObserveOnDispatcher:
messageBus.GetMessages<Message>().ObserveOnDispatcher().Subscribe(x => TestHanlder(x));
..........................Output.................................
Main Thread Id:9
Push ThreadId:10
------------------> UI Handler ThreadId: are missing not there!?
What I'm doing wrong here?!!!!!
【问题讨论】:
-
我的代码有什么问题?非常感谢任何帮助...
-
有很多“MessageBus”类。如果它在工作线程上产生消息,并非不可能,那么 ObserveOnDispatcher() 将使用错误的调度程序。
-
@HansPassant 好点我也认为 ObserveOnDispatcher 使用了错误的调度程序,但我如何证明这一点?我应该为 MessageBus 类使用其他实现吗?
标签: c# wpf system.reactive reactiveui message-bus