【发布时间】:2016-09-30 12:13:00
【问题描述】:
我有使用 BouncyCastle 生成的公共和私有 ECC:
Security.addProvider(new org.bouncycastle.jce.provider.BouncyCastleProvider());
ECNamedCurveParameterSpec ecSpec = ECNamedCurveTable
.getParameterSpec("secp192r1");
KeyPairGenerator g = KeyPairGenerator.getInstance("ECDSA", "BC");
g.initialize(ecSpec, new SecureRandom());
KeyPair pair = g.generateKeyPair();
System.out.println(Arrays.toString(pair.getPrivate().getEncoded()));
System.out.println(Arrays.toString(pair.getPublic().getEncoded()));
byte[] privateKey = new byte[]{48, 123, 2, 1, 0, 48, 19, 6, 7, 42, -122, 72, -50, 61, 2, 1, 6, 8, 42, -122, 72, -50, 61, 3, 1, 1, 4, 97, 48, 95, 2, 1, 1, 4, 24, 14, 117, 7, -120, 15, 109, -59, -35, 72, -91, 99, -2, 51, -120, 112, -47, -1, -115, 25, 48, -104, -93, 78, -7, -96, 10, 6, 8, 42, -122, 72, -50, 61, 3, 1, 1, -95, 52, 3, 50, 0, 4, 64, 48, -104, 32, 41, 13, 1, -75, -12, -51, -24, -13, 56, 75, 19, 74, -13, 75, -82, 35, 1, -50, -93, -115, -115, -34, -81, 119, -109, -50, -39, -57, -20, -67, 65, -50, 66, -122, 96, 84, 117, -49, -101, 54, -30, 77, -110, -122}
byte[] publicKey = new byte[]{48, 73, 48, 19, 6, 7, 42, -122, 72, -50, 61, 2, 1, 6, 8, 42, -122, 72, -50, 61, 3, 1, 1, 3, 50, 0, 4, 64, 48, -104, 32, 41, 13, 1, -75, -12, -51, -24, -13, 56, 75, 19, 74, -13, 75, -82, 35, 1, -50, -93, -115, -115, -34, -81, 119, -109, -50, -39, -57, -20, -67, 65, -50, 66, -122, 96, 84, 117, -49, -101, 54, -30, 77, -110, -122}
如何将它们转换为可以在https://github.com/kmackay/micro-ecc/blob/master/uECC.h 中重复使用的传统格式?我需要 24 字节的私钥和 48 字节的公钥,而现在是 125 和 75。
【问题讨论】:
-
“传统格式”是什么意思?是 PKCS#1 还是要提取公钥和私钥的参数?
-
我使用 secp192r1 曲线,所以我需要 24 字节的私钥和 48 字节的公钥长度。
-
您找到将 pkcs8 EC 密钥转换为 pkcs1 再转换回 pkcs8 的方法了吗?
标签: cryptography bouncycastle elliptic-curve java-security pkcs#8