使用 Python 为响应列表中的每个元素发出 API 请求 (LinkedIn)

Question

我有一个 LinkedIn 帖子 ID 列表。我需要通过另一个请求请求每个帖子的共享统计信息。

请求函数如下所示：

def ugcp_stats(headers):
    response = requests.get(f'https://api.linkedin.com/v2/organizationalEntityShareStatistics?q=organizationalEntity&organizationalEntity=urn%3Ali%3Aorganization%3A77487&ugcPosts=List(urn%3Ali%3AugcPost%3A{shid},urn%3Ali%3AugcPost%3A{shid2},...,urn%3Ali%3AugcPost%3A{shidx})', headers = headers)
    ugcp_stats = response.json()
    return ugcp_stats

urn%3Ali%3AugcPost%3A{shid},urn%3Ali%3AugcPost%3A{shid2},...,urn%3Ali%3AugcPost%3A{shidx} - 这些是共享 urn。它们的数量取决于我列表中的元素数量。

接下来我该怎么做？我是否应该计算列表中的元素数量并以某种方式修改请求 URL 以包含所有元素？或者也许我应该遍历列表并对每个元素发出单独的请求，然后将所有响应附加到一个 json 文件中？

我很挣扎，我不太确定如何写这个。我什至不知道如何将元素解析为请求。虽然我怀疑它可能看起来像这样：

for shid in shids:
    def ugcp_stats(headers):
        response = requests.get(f'https://api.linkedin.com/v2/organizationalEntityShareStatistics?q=organizationalEntity&organizationalEntity=urn%3Ali%3Aorganization%3A77487&ugcPosts=List(urn%3Ali%3AugcPost%3A & {shid})', headers = headers)
        ugcp_stats = response.json()
        return ugcp_stats

更新 - 关注您的分析 现在的代码如下所示：

    link = "https://api.linkedin.com/v2/organizationalEntityShareStatistics?q=organizationalEntity&organizationalEntity=urn%3Ali%3Aorganization%3A77487&ugcPosts=List"
def share_stats(headers, shids):
    # Local variable
    sample = ""
    # Sample the shids in the right pattern
    for shid in shids: sample += "urn%3Ali%3AugcPost%3A & {},".format(shid)
    # Get the execution of the string content
    response = eval(f"requests.get('{link}({sample[:-1]})', headers = {headers})")
    # Return the stats
    return response.json()
    if __name__ == '__main__':
        credentials = 'credentials.json'
        access_token = auth(credentials) # Authenticate the API
        headers = headers(access_token) # Make the headers to attach to the API call.
        share_stats = share_stats(headers) # Get shares
    print(share_stats)

但似乎什么都没有发生。它完成了脚本，但我什么也没得到。怎么了？

Answer 1

这只是我之前作为评论告诉你的证明。现在您将适应您的需求（即使我尝试为您做）:)

更新 - 根据您的反馈。

#// IMPORT
#// I'm assuming your are using "requests" library
#// PyCharm IDE show me like this library is not used, but "eval()" is using it
import requests

#// GLOBAL VARIABLES
link: str = "https://api.linkedin.com/v2/organizationalEntityShareStatistics?q=organizationalEntity&organizationalEntity=urn%3Ali%3Aorganization%3A77487&ugcPosts=List"


#// Your function logic updated
def share_stats(sheds: list, header: dict) -> any:
    # Local variable
    sample = ""

    # Sample the sheds in the right pattern
    for shed in sheds: sample += "urn%3Ali%3AugcPost%3A & {},".format(shed)

    # Get the execution of the string content
    response = eval(f"requests.get('{link}({sample[:-1]})', headers = {header})")

    # Return the stats as JSON file
    return response.json()


#// Run if this is tha main file
if __name__ == '__main__':
    #// An empty sheds list for code validation
    debug_sheds: list = []
    credentials: str = "credentials.json"

    #// For me I get an unresolved reference for "auth", for you shod be fine
    #// I'm assuming is your function for reading the file content and convert it to Python
    access_token = auth(credentials)    # Authenticate the API

    #// Your error was from this script line
    #// Error message: 'TypedDict' object is not callable
    #// Your code: headers = headers(access_token)
    #// When you want to get a dictionary value by a key use square brackets
    headers = headers[access_token]     # Make the headers to attach to the API call.

    #// Here you shood ged an error/warning because you do not provided the sheds first time
    #// Your code: share_stats = share_stats(headers)
    share_stats = share_stats(debug_sheds, headers)  # Get shares

    print(share_stats)