将我的应用程序与 twitter 连接起来

Question

我有一个示例，我收到 401 错误，因为消费者不正确或签名不匹配。如何将签名密钥放在这里，因为在我的工作 java 示例中有一个签名密钥，我想实现它.

public class TwitterApp {
private Twitter mTwitter;
private TwitterSession mSession;
private AccessToken mAccessToken;
private OAuthConsumer mHttpOauthConsumer;
private OAuthProvider mHttpOauthprovider;
private String mConsumerKey;
private String mSecretKey;
private ProgressDialog mProgressDlg;
private TwDialogListener mListener;
private Context context;

public static final String CALLBACK_URL = "twitterapp://connect";
private static final String TAG = "TwitterApp";

public TwitterApp(Context context, String consumerKey, String secretKey) {
    this.context    = context;

    mTwitter        = new TwitterFactory().getInstance();
    mSession        = new TwitterSession(context);
    mProgressDlg    = new ProgressDialog(context);

    mProgressDlg.requestWindowFeature(Window.FEATURE_NO_TITLE);

    mConsumerKey    = consumerKey;
    mSecretKey      = secretKey;

    mHttpOauthConsumer = new CommonsHttpOAuthConsumer(mConsumerKey, mSecretKey);
    mHttpOauthprovider = new CommonsHttpOAuthProvider("http://twitter.com/oauth/request_token",
                                                 "http://twitter.com/oauth/access_token",
                                                 "http://twitter.com/oauth/authorize");

    mAccessToken    = mSession.getAccessToken();

    configureToken();
}

public void setListener(TwDialogListener listener) {
    mListener = listener;
}

@SuppressWarnings("deprecation")
private void configureToken() {
    if (mAccessToken != null) {
        mTwitter.setOAuthConsumer(mConsumerKey, mSecretKey);

        mTwitter.setOAuthAccessToken(mAccessToken);
    }
}

public boolean hasAccessToken() {
    return (mAccessToken == null) ? false : true;
}

public void resetAccessToken() {
    if (mAccessToken != null) {
        mSession.resetAccessToken();

        mAccessToken = null;
    }
}

public String getUsername() {
    return mSession.getUsername();
}

public void updateStatus(String status) throws Exception {
    try {
        mTwitter.updateStatus(status);
    } catch (TwitterException e) {
        throw e;
    }
}

public void authorize() {
    mProgressDlg.setMessage("Initializing ...");
    mProgressDlg.show();

    new Thread() {
        @Override
        public void run() {
            String authUrl = "";
            int what = 1;

            try {
                authUrl = mHttpOauthprovider.retrieveRequestToken(mHttpOauthConsumer, CALLBACK_URL);    

                what = 0;

                Log.d(TAG, "Request token url " + authUrl);
            } catch (Exception e) {
                Log.d(TAG, "Failed to get request token");

                e.printStackTrace();
            }

            mHandler.sendMessage(mHandler.obtainMessage(what, 1, 0, authUrl));
        }
    }.start();
}

public void processToken(String callbackUrl)  {
    mProgressDlg.setMessage("Finalizing ...");
    mProgressDlg.show();

    final String verifier = getVerifier(callbackUrl);

    new Thread() {
        @Override
        public void run() {
            int what = 1;

            try {
                mHttpOauthprovider.retrieveAccessToken(mHttpOauthConsumer, verifier);

                mAccessToken = new AccessToken(mHttpOauthConsumer.getToken(), mHttpOauthConsumer.getTokenSecret());

                configureToken();

                User user = mTwitter.verifyCredentials();

                mSession.storeAccessToken(mAccessToken, user.getName());

                what = 0;
            } catch (Exception e){
                Log.d(TAG, "Error getting access token");

                e.printStackTrace();
            }

            mHandler.sendMessage(mHandler.obtainMessage(what, 2, 0));
        }
    }.start();
}

private String getVerifier(String callbackUrl) {
    String verifier  = "";

    try {
        callbackUrl = callbackUrl.replace("twitterapp", "http");

        URL url         = new URL(callbackUrl);
        String query    = url.getQuery();

        String array[]  = query.split("&");

        for (String parameter : array) {
             String v[] = parameter.split("=");

             if (URLDecoder.decode(v[0]).equals(oauth.signpost.OAuth.OAUTH_VERIFIER)) {
                 verifier = URLDecoder.decode(v[1]);
                 break;
             }
        }
    } catch (MalformedURLException e) {
        e.printStackTrace();
    }

    return verifier;
}

private void showLoginDialog(String url) {
    final TwDialogListener listener = new TwDialogListener() {
        @Override
        public void onComplete(String value) {
            processToken(value);
        }

        @Override
        public void onError(String value) {
            mListener.onError("Failed opening authorization page");
        }
    };

    new TwitterDialog(context, url, listener).show();
}

private Handler mHandler = new Handler() {
    @Override
    public void handleMessage(Message msg) {
        mProgressDlg.dismiss();

        if (msg.what == 1) {
            if (msg.arg1 == 1)
                mListener.onError("Error getting request token");
            else
                mListener.onError("Error getting access token");
        } else {
            if (msg.arg1 == 1)
                showLoginDialog((String) msg.obj);
            else
                mListener.onComplete("");
        }
    }
};

public interface TwDialogListener {
    public void onComplete(String value);       

    public void onError(String value);
}

}

我也有一个 java 的工作示例，我很容易获得令牌，但问题是它使用 DefaultOAuthConsumer 和 DefaultOAuthProvider 但是每当我在我的示例中尝试实现它时，我都会遇到通信错误，这就是我使用 CommonsHttpOAuthConsumer 的原因和 CommonsHttpOAuthProvider。

这是java工作代码

公共类主{

public static void main(String[] args) throws Exception {

    OAuthConsumer consumer = new DefaultOAuthConsumer(
            "iIlNngv1KdV6XzNYkoLA",
            "exQ94pBpLXFcyttvLoxU2nrktThrlsj580zjYzmoM",
            SignatureMethod.HMAC_SHA1);

    OAuthProvider provider = new DefaultOAuthProvider(consumer,
            "http://twitter.com/oauth/request_token",
            "http://twitter.com/oauth/access_token",
            "http://twitter.com/oauth/authorize");

    System.out.println("Fetching request token from Twitter...");

    // we do not support callbacks, thus pass OOB
    String authUrl = provider.retrieveRequestToken(OAuth.OUT_OF_BAND);

    System.out.println("Request token: " + consumer.getToken());
    System.out.println("Token secret: " + consumer.getTokenSecret());

    System.out.println("Now visit:\n" + authUrl
            + "\n... and grant this app authorization");
    System.out.println("Enter the PIN code and hit ENTER when you're done:");

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    String pin = br.readLine();

    System.out.println("Fetching access token from Twitter...");

    provider.retrieveAccessToken(pin);

    System.out.println("Access token: " + consumer.getToken());
    System.out.println("Token secret: " + consumer.getTokenSecret());

    URL url = new URL("http://twitter.com/statuses/mentions.xml");
    HttpURLConnection request = (HttpURLConnection) url.openConnection();

    consumer.sign(request);

    System.out.println("Sending request to Twitter...");
    request.connect();

    System.out.println("Response: " + request.getResponseCode() + " "
            + request.getResponseMessage());
}

}

我也不知道我在这里使用的回调 url 字符串..

Answer 1

CALLBACK_URL 应该匹配

<intent-filter> 

在您的 manifest.xml 中。

在你的代码sn-ps中，你是否声明并初始化了mHttpOathCosumer和provider？