【发布时间】:2020-12-16 22:08:08
【问题描述】:
这是我的请求代码。 aa 表示我的消费者密钥,bb 是 userAcessTokenSecret。为了安全起见,我更改了值。我不知道是因为 cursor 参数还是编码和散列值和键的方式。
public static void getLocationAndNameOfFollowers(String userAcessToken, String userAcessTokenSecret) throws IOException, InvalidKeyException, NoSuchAlgorithmException {
userAcessTokenSecret = "bb";
String signingKey = GenerateSignature.oAuthSigningKey("aa", userAcessTokenSecret);
long ts = new Timestamp(System.currentTimeMillis()).getTime() / 1000;
String timeStamp = String.valueOf(ts);
String nonce = GenerateSignature.generateNonce("aa", timeStamp);
String baseString = GenerateSignature.oAuthBaseString("GET", "https://api.twitter.com/1.1/followers/list.json?",
"cursor-1", "fHkdJVy3x1fKE1Yop9qraJyCp", userAcessToken, timeStamp, nonce);
String oauth_signature = GenerateSignature.oAuthSignature(baseString, signingKey);
JSONObject response = Unirest.get("https://api.twitter.com/1.1/followers/list.json?cursor=-1")
.header("Content-Type", "application/x-www-form-urlencoded")
.header("Authorization", "OAuth oauth_consumer_key=\"consumer_key\"," +
"oauth_token=" + "\"" + userAcessToken +"\""+ "," +
"oauth_signature_method=" + "\"HMAC-SHA1\"," +
"oauth_timestamp=" + "\""+timeStamp + "\"" + "," +
"oauth_nonce=" + "\""+nonce + "\"" + "," +
"oauth_version=\"1.0\"," +
"oauth_signature=" + "\"" +oauth_signature + "\"")
.asJson().getBody().getObject();
下面的代码包含我的辅助函数。
private static String percentEncoding(String originalString) {
String encodedString = Base64.getUrlEncoder().encodeToString(originalString.getBytes());
return encodedString;
}
public static String oAuthBaseString(String method, String url, String parameters, String key, String token, String timestamp, String nonce) {
System.out.println("generated sorted parameter string -> "+generateSortedParameterString(parameters, key, token, timeStamp , nonce));
String res = method + "&" + percentEncoding(url)
+ "&" + generateSortedParameterString(parameters, key, token, timeStamp , nonce);
System.out.println("oauth base string -> \n\n\n" + res);
return res;
}
public static String oAuthSignature(String baseString, String tokenSecret) throws NoSuchAlgorithmException, InvalidKeyException {
byte[] bytes = baseString.getBytes(StandardCharsets.UTF_8);
Mac mac = Mac.getInstance("HmacSHA1");
mac.init(new SecretKeySpec(bytes, "HmacSHA1"));
byte[] res = mac.doFinal(tokenSecret.getBytes(StandardCharsets.UTF_8));
return percentEncoding(Base64.getEncoder().toString());
}
public static String oAuthSigningKey(String consumerSecret, String accessTokenSecret) {
return consumerSecret + "&" + accessTokenSecret;
}
public static String generateNonce(String consumerKey, String timeStamp) {
String nonce = Base64.getEncoder().encodeToString((consumerKey + ":" + timeStamp).getBytes());
return nonce;
}
public static String generateSortedParameterString(String parameter, String key, String token, String timeStamp, String nonce) {
Map<String, String> parameters = new LinkedHashMap<>();
parameters.put("oauth_consumer_key", key);
parameters.put("oauth_nonce", nonce);
parameters.put("oauth_signature_method", "HMAC-SHA1");
parameters.put("oauth_timestamp", timeStamp);
parameters.put("oauth_token", token);
parameters.put("oauth_version", "1.0");
System.out.println("parameter map is here -> "+parameters);
String parameterString = parameters.entrySet().stream()
.sorted(Map.Entry.comparingByKey())
.map(e -> percentEncoding(e.getKey()) + "=" + percentEncoding(e.getValue()))
.collect(Collectors.joining("&"));
return parameterString;
}
我收到此回复
{"errors":[{"code":32,"message":"无法验证您的身份。"}]}
【问题讨论】:
-
Twitter4J 和其他几个库为您执行此操作,是否有理由自己实现此功能?
-
我不知道那个图书馆。我会看看它。谢谢。
-
如果您想在没有第三方库的情况下生成 Twitter API 签名,您可以参考this 回答,
标签: java api twitter encode signature