【发布时间】:2016-06-04 16:07:04
【问题描述】:
我正在尝试将登录的用户存储在新会话中,从数据库中获取信息,将其放入 json 数组,然后在 android 中获取数组并在布局中显示结果。但是,当我运行该应用程序时,从 php 文件返回的数组为空。但是,如果我要在 Postman 等不同的程序中测试 php 文件,我会得到正确的响应
{"result":[{"id":"12","fname":"C","lname":"Wei","username":"cw","email":"werrs.com"}]}
这里是php文件和java方法。
<?php
session_start();
if($_SERVER['REQUEST_METHOD'] == 'GET'){
$username = $_SESSION['username'];
$sql = "SELECT * FROM USER WHERE username = '$username'";
require_once('connect.inc.php');
$run = mysqli_query($conn, $sql);
$result = array();
while($row = mysqli_fetch_array($run)){
array_push($result, array(
'id' => $row['id'],
'fname' => $row['fname'],
'lname' => $row['lname'],
'username' => $row['username'],
'email' => $row['email'],
));
}
echo json_encode(array('result'=>$result));
mysqli_close($conn);
}
?>
在 Postman 中,它成功获取了登录用户,但在 android 中却没有。
private void getUserData() { StringRequest stringRequest = new
StringRequest(Request.Method.GET,
Config.SERVER_ADDRESS + "GetUserData.php",
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
JSONObject jsonObject = null;
try {
//json string to jsonobject
jsonObject = new JSONObject(response);
//get json sstring created in php and store to JSON Array
result = jsonObject.getJSONArray(Config.json_array);
//get username from json array
getUserInfo(result);
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
}
});
RequestQueue requestQueue = Volley.newRequestQueue(this);
requestQueue.add(stringRequest);
}
private void getUserInfo(JSONArray jsonArray){
for(int i = 0; i < jsonArray.length(); i++) {
try {
JSONObject json = jsonArray.getJSONObject(i);
userInfo.add(json.getString(Config.getUsername));
} catch (JSONException e) {
}
}
}
【问题讨论】:
标签: java php android mysql session