遍历 Firebase 数组

Question

当我得到数据库的快照时，我看到了这个：

{
    "9-17-2017" =     {
        "19:26:38" =         {
            1abA = 1ab;
            1abrA = 1;
            2abA = 2ab;
            2abrA = 2;
            3abA = 3ab;
            4abA = 4ab;
            5abA = 5a;
            6abA = 6ab;
            7abA = 7ab;
            Date = "9-17-2017";
            Time = "19:26:38";
            anA = an;
            apnA = apn;
            q1A = 1;
            q2A = 2;
            q3A = 3;
            q4A = 4;
            q5A = 5;
            q6A = 6;
        };
        "20:16:15" =         {
            1abA = 1qwe;
            1abrA = 3;
            2abA = "D.C.";
            2abrA = 7;
            3abA = wedded;
            4abA = wedge;
            5abA = qdwfeg;
            6abA = qwfegr;
            7abA = wedge;
            Date = "9-17-2017";
            Time = "20:16:15";
            anA = "we're";
            apnA = apn;
            q1A = 7;
            q2A = 2;
            q3A = 7;
            q4A = 4;
            q5A = 5;
            q6A = 7;
        };
    };
}

我希望能够将标签设置为键 1abA 的值，但我似乎无法找到对数组进行排序的方法。

我正在使用此代码获取快照：

let userID = Auth.auth().currentUser?.uid
let ref = Database.database().reference().child("users").child(userID!) ref.child("PostGameEval").observe(.value, with: { (snapshot) in
            print(snapshot.value!)
        })

Answer 1

我已经尝试过了，希望对你有帮助：

我已经把上图的数据如下：

这里dict相当于上面的snapshot.value：

    let dict = [
        "9-17-2017" :    [
                "19:26:38" :        [
                        "1abA" : "1ab",
                        "1abrA" : 1
                ],
                "20:16:15" :         [
                        "1abA" : "1qwe",
                        "1abrA" : 3

                ],
                "19:23:38" :        [
                        "1abA" : "1ab",
                        "1abrA" : 1
                ],
                "21:16:15" :         [
                        "1abA" : "1qwe",
                        "1abrA" : 3

                ]

        ],
        "9-16-2017":   [
                "19:20:38" :        [
                        "1abA" : "1ax",
                        "1abrA" : 4
                ],
                "20:01:15" :         [
                        "1abA" : "1qe",
                        "1abrA" : 0

                ],
                "19:23:38" :        [
                        "1abA" : "1ab",
                        "1abrA" : 1
                ],
                "21:16:15" :         [
                        "1abA" : "1qwe",
                        "1abrA" : 3

                ]

        ]

]

注意：我认为在您的情况下，您可以获得dict，如下所示：

if let dict = snaphot.value as? [String : [String: [String: Any]] {
    //then use the following code here
}

现在获取键 1abA 的值我使用了以下代码：

let keys = Array(dict.keys)

var myLabel = ""
for i in 0..<keys.count {
        if let innerDict = dict[keys[i]] {
                let innerKeys = Array((innerDict).keys)
                let sortedInnerKeys = innerKeys.sorted(by: { $0 > $1} )
                for j in 0..<2 {
                        if let tempDict = innerDict[sortedInnerKeys[j]] {
                                //myLabel = tempDict["1abA"] as! String
                                print("Value of Key 1abA for innerKey \(sortedInnerKeys[j]) is \(tempDict["1abA"] ?? "")")
                                print("Value of Key 1abrA for innerKey \(sortedInnerKeys[j]) is \(tempDict["1abrA"] ?? "")")
                        }
                }
        }

}

输出：

innerKey 21:16:15 的 Key 1abA 的值为 1qwe

innerKey 21:16:15 的 Key 1abrA 的值为 3

innerKey 20:01:15 的 Key 1abA 的值为 1qe

innerKey 20:01:15 的 Key 1abrA 的值为 0

innerKey 21:16:15 的 Key 1abA 的值为 1qwe

innerKey 21:16:15 的 Key 1abrA 的值为 3

innerKey 20:16:15 的 Key 1abA 的值为 1qwe

innerKey 20:16:15 的键 1abrA 的值为 3