如何从 Firebase 数据中获取特定的键值？

Question

{
  "DIV_1" : {
    "ACTINACT" : 1,
    "COORDINATOR" : "10CA056",
    "DIV_CODE" : "BSL",
    "DIV_ID" : 1,
    "DIV_NAME" : "Bhusawal",
    "ERP_LOC_CODE" : "CRB",
    "MTIME" : "2017-04-08T11:02:59",
    "ZONE_ID" : "ZONE_1"
  },

  "DIV_10" : {
    "ACTINACT" : 1,
    "COORDINATOR" : "06CS011",
    "DIV_CODE" : "UMB",
    "DIV_ID" : 10,
    "DIV_NAME" : "Ambala",
    "ERP_LOC_CODE" : "NRA",
    "MTIME" : "2017-04-08T11:02:59",
    "ZONE_ID" : "ZONE_3"
  }
}

如何获得 DIV_ID？ 最初我需要比较键（Ex::Here DIV_10），然后需要获取 DIV_NAME。 提前谢谢...

Answer 1

我假设 DIV_1 和 DIV_10 的父级是根。如果你有DIV_ID 的值，比如“1”或“10”，并且需要得到DIV_NAME 的值，那么你应该这样做：

int divId = 1; // sample
FirebaseDatabase.getInstance().getReference().orderByChild("DIV_ID").equalTo(divId)
    .addValueEventListener(new ValueEventListener() {
        ... onDataChange(DataSnapshot dataSnapshot) {
             for (DataSnapshot snapshot : dataSnapshot.getChildren()) {
                 String divName = snapshot.child("DIV_NAME").getValue(String.class);
                 // there you go
                 // and please check if you have more than 1 value as result
             }
        }
        ...
    }

但是，如果您有 DIV_1 或 DIV_10 这样的键值，那么它应该会容易得多。像这样：

String key = "DIV_1";
FirebaseDatabase.getInstance().getReference(key)
    .addValueEventListener(new ValueEventListener() {
        ... onDataChange(DataSnapshot dataSnapshot) {
             String divName = snapshot.child("DIV_NAME").getValue(String.class);
             // note that in this sample, it doesn't need to loop, because:
             // data you get here is one level deeper than data you got on first sample
        }
        ...
    }

希望对你有帮助