如何通过 API 响应使用 Postman 发出的请求以适当的错误消息进行响应答案

【问题标题】：How to respond with appropriate error message through an API response to request made using Postman如何通过 API 响应使用 Postman 发出的请求以适当的错误消息进行响应
【发布时间】：2020-09-05 04:24:06
【问题描述】：

我创建了一个包含所有 crud 操作的 restful Api。当我测试通过 id 获取员工时，我无法显示错误消息。即使我在该 ID 不存在记录时抛出异常。

这是我的控制器代码...

    @GetMapping("/employee/{id}")
    public ResponseEntity<Employee> getEmployeeById(@PathVariable("id") long employeeId) throws ResourceNotFoundException{

        Employee employee=service.getEmployeeById(employeeId).orElseThrow(()->new ResourceNotFoundException("Employee not found for this id :"+employeeId));

        return new ResponseEntity<Employee>(employee, HttpStatus.OK);

和我的异常类代码

package com.mystyle.exception;

import org.springframework.http.HttpStatus;
import org.springframework.web.bind.annotation.ResponseStatus;

@ResponseStatus(value=HttpStatus.NOT_FOUND)
public class ResourceNotFoundException extends RuntimeException {

    /**
     * 
     */
    private static final long serialVersionUID = 1L;


    public ResourceNotFoundException(String message){
        super(message);
    }
}

还有我的邮递员错误信息

{
    "timestamp": "2020-05-19T06:21:10.172+00:00",
    "status": 404,
    "error": "Not Found",
    "message": "",
    "path": "/api/v1/employee/2"
}

【问题讨论】：

你的异常是否在堆栈跟踪中抛出？
您的问题是，您想显示带有适当 HTTP 错误的自定义错误消息吗？如果您使用自定义异常。建议你看看这个帖子：baeldung.com/exception-handling-for-rest-with-spring

标签： java spring-boot exception postman

【解决方案1】：

在模型包下为错误消息创建一个类。

 public class ErrorMessage {

  private String errorMessage;
  private int errorCode;
  private String documentation;
  public ErrorMessage() {

  }
  public ErrorMessage(String errorMessage, int errorCode, String documentation) {
      this.errorMessage = errorMessage;
      this.errorCode = errorCode;
      this.documentation = documentation;
  }
  public String getErrorMessage() {
      return errorMessage;
  }
  public void setErrorMessage(String errorMessage) {
      this.errorMessage = errorMessage;
  }
  public int getErrorCode() {
      return errorCode;
  }
  public void setErrorCode(int errorCode) {
      this.errorCode = errorCode;
  }
  public String getDocumentation() {
      return documentation;
  }
  public void setDocumentation(String documentation) {
      this.documentation = documentation;
  }

   }

2.在异常包下创建Custome Exception类，生成Serial Version UID。

public class ResourceNotFoundException extends RuntimeException{

    /**
     * 
     */
    private static final long serialVersionUID = -2491065979792776613L;

    public ResourceNotFoundException(String msg)
    {
        super(msg);
    }

}

3.在异常包下创建ExceptionHandler类

@RestControllerAdvice
public class ResourceNotFoundExceptionHandler {

    @ExceptionHandler(ResourceNotFoundException.class)
    public ResponseEntity<ErrorMessage> toResponse(ResourceNotFoundException ex)
    {
        ErrorMessage errorMessage=new ErrorMessage(ex.getMessage(),404,"www.benz.com");

        return new ResponseEntity<ErrorMessage>(errorMessage,HttpStatus.NOT_FOUND);
    }
}

【讨论】：