【问题标题】:Spring-Hibernate, Many to Many relationship querySpring-Hibernate,多对多关系查询
【发布时间】:2015-07-20 19:02:18
【问题描述】:

我有两个 bean 类 Student 和 Course ,它们之间有多对多的关系。例如。一名学生可以注册多门课程,反之亦然。我使用 HibernateTemplate 将对象保存到 Oracle DB 中。以下是 Student、Course 和 StudentDao 类。

学生班

package com.springhibernate;

import java.util.Set;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.JoinTable;
import javax.persistence.ManyToMany;
import javax.persistence.Table;

@Entity
@Table(name="Student")

public class Student {
    private int studentId;
    private String firstName;
    private String lastName;
    private Set<Course> courses;

@Id
@Column(name="student_id")
public int getStudentId() {
    return studentId;
}
public void setStudentId(int studentId) {
    this.studentId = studentId;
}

@Column(name="first_name")
public String getFirstName() {
    return firstName;
}
public void setFirstName(String firstName) {
    this.firstName = firstName;
}

@Column(name="last_name")
public String getLastName() {
    return lastName;
}
public void setLastName(String lastName) {
    this.lastName = lastName;
}

@ManyToMany(cascade = CascadeType.ALL)
@JoinTable(name = "Student_Course", joinColumns = @JoinColumn(name = "student_id"), inverseJoinColumns = @JoinColumn(name = "course_id"))
public Set<Course> getCourses() {
    return courses;
}
public void setCourses(Set<Course> courses) {
    this.courses = courses;
}

}

StudentDao 课堂

package com.springhibernate;

import java.util.List;

import org.springframework.orm.hibernate3.HibernateTemplate;

public class StudentDao {

private static Helper helper = new Helper();

HibernateTemplate template;
public void setTemplate(HibernateTemplate template) {
    this.template = template;
}

// method to save student
public void saveStudent(Student s) {
    template.save(s);
}

// method to return one employee of given id
public Student getById(int id) {
    Student s = (Student) template.get(Student.class, id);
    return s;
}

public List<Course> findCourse(){
    List<Course> list = template.find("from Course");
    return list;
}
}

课程班

package com.springhibernate;

import java.util.Set;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.ManyToMany;
import javax.persistence.Table;


@Entity
@Table(name="Course")
public class Course {

private int courseId;
private String courseName;
private Set<Student> students;

@Id
@Column(name="course_id")
public int getCourseId() {
    return courseId;
}
public void setCourseId(int courseId) {
    this.courseId = courseId;
}

@Column(name="course_name")
public String getCourseName() {
    return courseName;
}
public void setCourseName(String courseName) {
    this.courseName = courseName;
}

@ManyToMany(cascade=CascadeType.ALL,mappedBy="courses")
public Set<Student> getStudents() {
    return students;
}
public void setStudents(Set<Student> students) {
    this.students = students;
}

@Override
public int hashCode() {
    // TODO Auto-generated method stub
    return this.courseId;
}

@Override
public boolean equals(Object o) {
    // TODO Auto-generated method stub
    Course temp = (Course) o;
    return (this.courseId==temp.courseId);

}
}

我有以下两个查询

  1. 我能够成功地将数据保存在 student_course 表中。我想知道我是否想从 student_course 表中检索数据,我该如何使用 HibernateTemplate 或者有其他方法吗? 例如,查询就像

    select course_id from student_course where student_id=1
    

    请注意,我只希望课程 ID 列不完整。

  2. 如果在 student_course 表中我想要多列 course_name(来自 course 表),我该怎么做?

【问题讨论】:

    标签: java spring oracle hibernate


    【解决方案1】:

    您可以通过以下方式执行此操作,但请记住,HibernateTemplate 是一个旧 API,您应该使用例如 EntityManager(Factory)。 您可以通过 Peristence 类获取它。

    hibernateTemplate.execute(new HibernateCallback<List>() {
    
        public String doInHibernate(Session s)
                throws HibernateException, SQLException {
            SQLQuery sql=s.createSQLQuery("select course_id from student_course where student_id=?");
                sql.setParameter(0, adventureId);
            sql.addScalar(studentID);
            return sql.list();
        }
    });
    

    【讨论】:

    • 我通过以下方式更改了 StudentDao 代码.. public List findCourse(final int sid){ List list = template.execute(new HibernateCallback() { public List doInHibernate(Session s) throws HibernateException,SQLException { SQLQuery sql = s.createSQLQuery("select course_id from student_course where student_id=?"); sql.setParameter(0, sid); return sql.list(); } });返回列表;输出:Hibernate: select course_id from student_course where student_id=?注册课程为:null null null
    • 是否可以回答我的 2 查询?
    • 您的一般问题的用例是有问题的。为什么不让学生在对象级别上导航到课程并获得他们的名字? hibernate的目的是对关系数据库进行抽象。
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