【发布时间】:2020-12-19 19:21:54
【问题描述】:
我正在重构我的代码,并且我在父级中有一些逻辑,需要评估其子级所具有的所有输入的值。为此,我在父级中创建了 4 个引用,并将它们作为道具传递给其子级。如下:
// References (will be used in multiple functions)
usernameInput = createRef(null);
emailInput = createRef(null);
passwordInput = createRef(null);
repeatPasswordInput = createRef(null);
...
render() {
return (
<View>
<Form1 usernameInputRef={usernameInput} emailInputRef={emailInput} />
<Form2 passwordInputRef={passwordInput} repeatPasswordInputRef={repeatPasswordInput} />
</View>
);
}
在每个孩子身上,我都在这样做:
// This is Child1. For Child2 gonna be the same but with its props.
const {
usernameInputRef,
emailInputRef,
} = props;
return (
<>
<TextInput
ref={usernameInputRef}
...
/>
<TextInput
ref={emailInputRef}
/>
</>
);
当我尝试访问父节点中每个子节点的值时,问题就来了……如果我这样做:
const username = this.usernameInput.current.props.value; // <--- Works if the input is in the same component, and not in the child.
console.log(username);
我得到“空”。
有什么想法吗?在将我的代码重构为多个组件之前,这是可行的......
更新
文本输入代码:
import React from "react";
import { View, StyleSheet } from "react-native";
import { TextInput as RNPTextInput, useTheme } from "react-native-paper";
const TextInput = forwardRef((props, ref) => {
const { colors } = useTheme();
let {
placeholder,
multiline,
maxLength,
secureTextEntry,
color,
icon,
counter,
onChange,
onSubmit,
onFocus,
containerStyle,
} = props;
...
return (
<>
<View style={containerStyle || styles.inputContainer}>
<RNPTextInput
ref={ref}
...
【问题讨论】:
-
TextInput对ref做了什么,它是否支持转发refs? reactjs.org/docs/forwarding-refs.html -
@Aivaras 我已经用 TextInput 代码更新了这个问题。基本上这是 react-native-paper TextInput 的包装
标签: javascript reactjs react-native components