【发布时间】:2018-09-23 16:59:18
【问题描述】:
我无法使用 GuzzleHttp 在 POST 请求中传递版本参数。
客户端错误:GET https://gateway.watsonplatform.net/tone-analyzer/api/v3/tone 导致 400 Bad Request 响应:{"code":400,"sub_code":"C00005","error":"URL 中缺少次要版本参数。要使用最新版本版本,添加th(截断...)
这是我最近尝试过的:
$client = new \GuzzleHttp\Client([
'base_uri' => 'https://gateway.watsonplatform.net/'
]);
$toneAnalyserResponse = $client->request('POST', 'tone-analyzer/api/v3/tone', [
'auth' => ['{username}', '{password}'],
'headers' => [
'Content-Type' => 'text/plain',
],
'form_params' => [
'version' => '2017-09-21',
'tone_input' => $text,
'sentences' => true
]
]);
这也失败了:
$client = new \GuzzleHttp\Client([
'base_uri' => 'https://gateway.watsonplatform.net/'
]);
$toneAnalyserResponse = $client->request('POST', 'tone-analyzer/api/v3/tone', [
'auth' => ['{username}', '{password}'],
'headers' => [
'Content-Type' => 'text/plain',
],
'version' => '2017-09-21',
'tone_input' => $text,
'sentences' => true
]);
如果使用 GET 而不是 POST,也会失败。
如果我更改 URI 并添加版本,那么它工作正常(好吧,它失败了,因为它没有在请求中分析的文本):
更改:tone-analyzer/api/v3/tone
收件人:tone-analyzer/api/v3/tone?version=2017-09-21
所以,我想问题是如何在使用 GuzzleHttp 的请求中传递 URL 参数?
注意:我的 CURL 命令工作正常(http 200):
curl -X POST -u "{username}":"{password}" --header 'Content-Type: text/plain' --header 'Accept: application/json' --header 'Content-Language: en' --header 'Accept-Language: en' -d 'I hate these new features On #ThisPhone after the update.\r\n \
I hate #ThisPhoneCompany products, you%27d have to torture me to get me to use #ThisPhone.\r\n \
The emojis in #ThisPhone are stupid.\r\n \
#ThisPhone is a useless, stupid waste of money.\r\n \
#ThisPhone is the worst phone I%27ve ever had - ever ????.\r\n \
#ThisPhone another ripoff, lost all respect SHAME.\r\n \
I%27m worried my #ThisPhone is going to overheat like my brother%27s did.\r\n \
#ThisPhoneCompany really let me down... my new phone won%27t even turn on.' 'https://gateway.watsonplatform.net/tone-analyzer/api/v3/tone?version=2017-09-21&sentences=true'
【问题讨论】: