我正在尝试使用复杂的数组创建一个放置请求和删除请求

Question

我正在尝试创建一个 put 请求并删除，但我不知道如何处理 DUMMY-PLACES。我将从开头（id、内容）获取，默认情况下完成的是 false（它是dummy DB ) 例如 (6,test6) 当然这是 byIds 中的数字需要相同“6”

const express = require("express");

const router = express.Router();

const DUMMY_PLACES = [
  {
    todos: {
      allIds: [1, 2, 3, 4],
      byIds: {
        "1": {
          content: "test1",
          completed: false,
        },
        "2": {
          content: "test2",
          completed: false,
        },
        "3": {
          content: "test3\\",
          completed: false,
        },
        "4": {
          content: "test4",
          completed: false,
        },
      },
    },
    visibilityFilter: "all",
  },
];

router.get("/todos", (req, res, next) => {
  try {
    const place = DUMMY_PLACES;
    console.log(place);
    res.json({ place });
  } catch (err) {
    next({ status: 400, message: "failed to get todos" });
  }
  // => { place } => { place: place }
});

router.put("/todos/", async (req, res, next) => {
  const { id, content } = req.body;
  try {
    todo = DUMMY_PLACES;
    console.log(todo.todos);
  } catch (err) {
    next({ status: 400, message: "failed to update todo" });
  }
});

module.exports = router;

Answer 1

要编辑单个待办事项，首先检查它是否确实存在并相应更新。

router.put("/todos", async (req, res, next) => {
  const { id, content } = req.body;
  // Check if todo actually exists
  const todoExists = DUMMY_PLACES[0].todos.byIds.hasOwnProperty(id);
  if (!todoExists) {
    next({ status: 400, message: `todo with id ${id} does not exist` });
  }
  // Update todo
  DUMMY_PLACES[0].todos.byIds[id].content = content;
  res.sendStatus(200);  
});

要删除待办事项，请从 byIds 对象中删除键

router.put("/todos", async (req, res, next) => {
  const { id } = req.body;
  delete DUMMY_PLACES[0].todos.byIds[id];
  res.sendStatus(200);  
});