【问题标题】:Make current file & the extension with condor match output & error files? (to have PBS and Slurm have same output files)使用秃鹰匹配输出和错误文件制作当前文件和扩展名? (让 PBS 和 Slurm 具有相同的输出文件)
【发布时间】:2021-05-16 17:54:51
【问题描述】:

如何让 condor 将我的文件命名如下:

meta_learning_experiments_submission.py.e451863 meta_learning_experiments_submission.py.o444375

$(FILENAME).e$(CLUSTER)
$(FILENAME).e$(CLUSTER)

我试过了,但它似乎不起作用。

例如以便在我执行qsub 时匹配 PBS 的默认行为?


我也想知道如何让 slurm 也匹配它,这将是完美的(所以所有三个集群都在工作)。

我试过了:

#SBATCH --error="(filename).%j.%N.err"

但这没有用


赏金

我想自动设置文件名而不用硬编码。


相关:


这里是我当前的提交文件:

####################
#
# Experiments script
# Simple HTCondor submit description file
#
#
# chmod a+x test_condor.py
# chmod a+x experiments_meta_model_optimization.py
# chmod a+x meta_learning_experiments_submission.py
# chmod a+x download_miniImagenet.py
# chmod a+x ~/meta-learning-lstm-pytorch/main.py
# chmod a+x /home/miranda9/automl-meta-learning/automl-proj/meta_learning/datasets/rand_fc_nn_vec_mu_ls_gen.py
# chmod a+x /home/miranda9/automl-meta-learning/automl-proj/experiments/meta_learning/supervised_experiments_submission.py
# chmod a+x /home/miranda9/automl-meta-learning/results_plots/is_rapid_learning_real.py
# condor_submit -i
# condor_submit job.sub
#
####################

Path = /home/miranda9/automl-meta-learning/
Path = /home/miranda9/ML4Coq/

# Executable = /home/miranda9/automl-meta-learning/automl-proj/experiments/meta_learning/supervised_experiments_submission.py
# Executable = /home/miranda9/automl-meta-learning/automl-proj/experiments/meta_learning/meta_learning_experiments_submission.py
# Executable = /home/miranda9/meta-learning-lstm-pytorch/main.py
# Executable = /home/miranda9/automl-meta-learning/automl-proj/meta_learning/datasets/rand_fc_nn_vec_mu_ls_gen.py
# Executable = /home/miranda9/automl-meta-learning/results_plots/is_rapid_learning_real.py

## Output Files
Log          = experiment_output_job.$(CLUSTER).log.out
Output       = experiment_output_job.$(CLUSTER).out.out
Error        = experiment_output_job.$(CLUSTER).err.out

Output = %(FILENAME).o$(CLUSTER)

# Use this to make sure 1 gpu is available. The key words are case insensitive.
# REquest_gpus = 1
# requirements = (CUDADeviceName != "Tesla K40m")
# requirements = (CUDADeviceName == "Quadro RTX 6000")

# requirements = ((CUDADeviceName = "Tesla K40m")) && (TARGET.Arch == "X86_64") && (TARGET.OpSys == "LINUX") && (TARGET.Disk >= RequestDisk) && (TARGET.Memory >= RequestMemory) && (TARGET.Cpus >= RequestCpus) && (TARGET.gpus >= Requestgpus) && ((TARGET.FileSystemDomain == MY.FileSystemDomain) || (TARGET.HasFileTransfer))
# requirements = (CUDADeviceName == "Tesla K40m")
# requirements = (CUDADeviceName == "GeForce GTX TITAN X")

# Note: to use multiple CPUs instead of the default (one CPU), use request_cpus as well
# Request_cpus = 4
Request_cpus = 16

# E-mail option
Notify_user = me@gmail.com
Notification = always

Environment = MY_CONDOR_JOB_ID= $(CLUSTER)

# "Queue" means add the setup until this line to the queue (needs to be at the end of script).
Queue

或者,如果我可以使用我的可执行脚本作为提交脚本,顶部的参数也​​可以使用

我通常使用我的提交脚本与我的可执行脚本相同,例如查看我的 qsub 示例:

#!/homes/miranda9/.conda/envs/automl-meta-learning/bin/python
#PBS -V
#PBS -M mee@gmail.com
#PBS -m abe
#PBS -lselect=1:ncpus=112

import sys
import os

for p in sys.path:
    print(p)

print(os.environ)

【问题讨论】:

  • 您希望 FILENAME 成为此处提交文件的名称吗?
  • @JohnKnoeller 是的,我希望变量 FILENAME 保存当前文件名的字符串,仅此而已。
  • $(SUBMIT_FILE) 保存提交文件的名称,而 condor_submit 正在处理它。这有帮助吗?
  • @JohnKnoeller,不幸的是,这没有帮助。它使用名称 job.sub 而不是我的可执行文件,例如Executable = /home/miranda9/automl-meta-learning/test_condor.py。我想要的是从我的可执行文件路径中提取字符串test_condor.py。
  • @JohnKnoeller 或者,如果您知道如何直接提交我的 python/bash 脚本而不是通过此提交脚本,那也可以,然后我将参数附加在顶部(我这样做的方式是 slurm或 qsub,让我粘贴我的 qsub 提交文件示例以显示我的内容,请参阅问题的编辑)。

标签: hpc slurm pbs condor


【解决方案1】:

HTCondor 默认不设置 FILENAME,但你可以自己设置,例如

FILENAME = meta_learning_experiments_submission.py
output = $(FILENAME).o.$(CLUSTER)
error  = $(FILENAME).e.$(CLUSTER)

【讨论】:

  • 但如何将其附加到整个路径?通常我有整个绝对路径...
  • 这些秃鹰文件是什么语言的?
  • 我想自动设置文件名而不用硬编码。
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