mysql - 无法让查询工作

Question

我一辈子都看不出这里出了什么问题。它很可能是愚蠢的，但我目前对此视而不见！我有一个问题：

SELECT 
Links.Title,
(6371 * acos( cos( radians(43.4347229) ) * cos( radians( Links.Latitude ) ) * cos( radians( Links.Longitude ) - radians(6.737222195) ) + sin( radians(43.4347229) ) * sin( radians( Links.Latitude ) ) ) AS distance 
FROM CatLinks,Links WHERE CatLinks.LinkID = Links.ID AND (Links.ID IN (16650,17190,153344) AND Links.isValidated = 'Yes' AND Links.PropertyType IN (1,2,3) AND Links.priceSort <= '9999' AND Links.PropertyType IN (1,2,3) AND Links.priceSort < '9999') ORDER BY distance LIMIT 0,50

..我得到一个错误：

错误：无法执行查询：无法执行查询：'SELECT Links.Title, (6371 * acos( cos( 弧度(43.4347229) ) * cos( 弧度( Links.Latitude ) ) * cos( 弧度( Links.Longitude ) - 弧度（6.737222195））+ sin（弧度（43.4347229））* sin（弧度（ Links.Latitude ) ) ) AS 距离 CatLinks,Links WHERE CatLinks.LinkID = Links.ID AND (Links.ID IN (16650,17190,153344)) ORDER BY distance LIMIT 0,50'：您的 SQL 语法有错误； 检查与您的 MySQL 服务器版本相对应的手册 在 'AS 距离 FROM CatLinks,Links WHERE 附近使用正确的语法 CatLinks.LinkID =' 在第 3 行

即使将其精简为更简单的查询，也不想工作：

SELECT 
    glinks_Links.Title,
    (6371 * acos( cos( radians(43.4347229) ) * cos( radians( glinks_Links.Latitude ) ) * cos( radians( glinks_Links.Longitude ) - radians(6.737222195) ) + sin( radians(43.4347229) ) * sin( radians( glinks_Links.Latitude ) ) ) AS distance 
    FROM glinks_CatLinks,glinks_Links ORDER BY distance LIMIT 0,50

我整个上午都在讨论这个问题，所以任何建议都将不胜感激！

Answer 1

您忘记关闭括号（sin( radians( Links.Latitude ) ) ) ) 附近）。试试这个

SELECT
    Links.Title,
    (
        6371 * acos(
            cos(radians(43.4347229)) * cos(radians(Links.Latitude)) * cos(
                radians(Links.Longitude) - radians(6.737222195)
            ) + sin(radians(43.4347229)) * sin(radians(Links.Latitude))
        )
    ) AS distance
FROM
    CatLinks,
    Links
WHERE
    CatLinks.LinkID = Links.ID
AND (
    Links.ID IN (16650, 17190, 153344)
    AND Links.isValidated = 'Yes'
    AND Links.PropertyType IN (1, 2, 3)
    AND Links.priceSort <= '9999'
    AND Links.PropertyType IN (1, 2, 3)
    AND Links.priceSort < '9999'
)
ORDER BY
    distance
LIMIT 0,50