【发布时间】:2019-10-16 05:05:06
【问题描述】:
是否可以在模型上构建以下查询,而不是对原始 sql 使用 sequilize.query()
select
queue,
count(*) total,
sum(case when type = 'Proactive' then 1 else 0 end) proactive,
sum(case when type = 'Reactive' then 1 else 0 end) reactive
from "OpenIncidents"
group by queue
order by total DESC;
我厌倦了将 sequelize.fn() 用于聚合函数,但在文档中没有发现任何关于 CASE WHEN 支持聚合函数的内容。
我目前使用原始查询
return sequelize.query(
`
SELECT
queue,
COUNT(*) total,
SUM(CASE WHEN type = 'Proactive' THEN 1 ELSE 0 END) proactive,
SUM(CASE WHEN type = 'Reactive' THEN 1 ELSE 0 END) reactive
FROM "OpenIncidents"
GROUP BY queue
ORDER BY total DESC;
`,
{ type: sequelize.QueryTypes.SELECT })
.then(queues => res.json(queues))
.catch(err => res.status(400).json(err));
有什么方法可以直接在 Sequelize 模型上进行,如下所示
return OpenIncident.findAll({
attributes:[
'queue',
[sequelize.fn('COUNT', sequelize.col('id')), 'total'],
[sequelize.fn('SUM', CASE_WHEN_STATEMENT, 'proactive'],
[sequelize.fn('SUM', CASE_WHEN_STATEMENT), 'reactive']
],
group: ['queue'],
order: [sequelize.fn('COUNT', sequelize.col('id')), 'DESC']
})
【问题讨论】:
标签: node.js postgresql sequelize.js