【发布时间】:2021-08-19 08:10:40
【问题描述】:
我正在尝试在 React.js 中创建一个线条和不喜欢按钮。我有两个包含谷歌图标的标签,点击图标后,它们应该实时更改而无需刷新页面。
但如果不刷新页面,它们就不会改变。我正在使用 MacBook Air,并且同时使用 Safari 浏览器 和 Brave 浏览器,但它无法正常工作。
我的页面编码如下:-
import React, { useState, useEffect, useContext } from 'react';
import {UserContext} from '../../App';
const Home = () => {
const [data, setData] = useState([]);
const { state, dispatch } = useContext(UserContext); // eslint-disable-line
useEffect(() => {
fetch('/allpost', {
headers: {
"Authorization": "Bearer " + localStorage.getItem("jwt")
}
}).then(res => res.json()).then(result => {
setData(result.posts);
});
}, []);
const likePost = (id) => {
fetch('/like', {
method: "put",
headers: {
"Content-Type": "application/json",
"Authorization": "Bearer " + localStorage.getItem("jwt")
},
body: JSON.stringify({
postId: id
})
}).then(res => res.json()).then(result => {
const newData = data.map(item => {
if (item._id == result._id) { // eslint-disable-line
return result;
} else {
return item;
}
})
setData(newData);
}).catch(err => {
console.log(err);
});
}
const dislikePost = (id) => {
fetch('/dislike', {
method: "put",
headers: {
"Content-Type": "application/json",
"Authorization": "Bearer " + localStorage.getItem("jwt")
},
body: JSON.stringify({
postId: id
})
}).then(res => res.json()).then(result => {
const newData = data.map(item => {
if (item._id == result._id) { // eslint-disable-line
return result;
} else {
return item;
}
})
setData(newData);
}).catch(err => {
console.log(err);
});
}
return (
<div className="home">
{
data.map(item => {
return (
<div className="card home-card" style={{ borderRadius:"6px" }} key={item._id}>
<h6 style={{ paddingLeft: "10px", paddingTop:"10px", fontSize:"17px" }}>{ item.postedBy.name }</h6>
<div className="card-image">
<img src={ item.photo } style={{ paddingLeft:"6px", paddingRight:"6px" }} alt="Posted photograph" />
</div>
<div className="card-content">
{item.likes.includes(state._id)
?
<i className="material-icons" style={{ color: "red" }} onClick={() => { dislikePost(item._id) }}>favorite_border</i>
:
<i className="material-icons" style={{ color: "red" }} onClick={() => {likePost(item._id)}}>favorite</i>
}
<h6>{item.likes.length} likes</h6>
<h6>{ item.title }</h6>
<p>{ item.body }</p>
<input type="text" placeholder="Add a comment here." />
</div>
</div>
);
})
}
</div>
);
}
export default Home;
我特别提到了我的图标更改逻辑的编写位置。如下:
<div className="card-content">
{item.likes.includes(state._id)
?
<i className="material-icons" style={{ color: "red" }} onClick={() => { dislikePost(item._id) }}>favorite_border</i>
:
<i className="material-icons" style={{ color: "red" }} onClick={() => {likePost(item._id)}}>favorite</i>
}
<h6>{item.likes.length} likes</h6>
<h6>{ item.title }</h6>
<p>{ item.body }</p>
<input type="text" placeholder="Add a comment here." />
</div>
【问题讨论】:
-
那么问题是您的逻辑仅更新本地
data状态而不是从上下文提供的state?state尤其是state._id代表什么? -
正如@DrewReese 指出的那样。问题在这里
item.likes.includes(state._id)。所以 onClick 除了触发你需要更新你的上下文的状态。
标签: javascript html node.js reactjs conditional-statements