【发布时间】:2014-02-19 07:40:31
【问题描述】:
我有一个简单的代码,它为特定路由提供 JSON 响应。这是我当前的代码:
var express = require('express')
, async = require('async')
, http = require('http')
, mysql = require('mysql');
var app = express();
var connection = mysql.createConnection({
host: 'localhost',
user: '****',
password: "****",
database: 'restaurants'
});
connection.connect();
// all environments
app.set('port', process.env.PORT || 1235);
app.use(express.static(__dirname + '/public/images'));
app.get('/DescriptionSortedRating/',function(request,response){
var name_of_restaurants;
async.series( [
// Get the first table contents
function ( callback ) {
connection.query('SELECT * FROM restaurants ORDER BY restaurantRATING', function(err, rows, fields)
{
console.log('Connection result error '+err);
name_of_restaurants = rows;
callback();
});
}
// Send the response
], function ( error, results ) {
response.json({
'restaurants' : name_of_restaurants
});
} );
} );
http.createServer(app).listen(app.get('port'), function(){
console.log('Express server listening on port ' + app.get('port'));
});
我怎样才能做出与上面的 JSON 等效的 XML 响应?
【问题讨论】:
标签: node.js express node-mysql