angular js ui-select选项重复不适用于对象数组

Question

我正在使用 Angular 用户界面选择。我的模型和 ui-select 选项数组不同。在更改值时，它不会更新并且不显示选项。我将选定的对象 ID 存储在“pmpo”中，我想在加载时显示 pmptnk 对象数组中的选定对象。但不工作。有人告诉我做错了什么。

我的模型对象

  pmpo:877
  pmptnk:[0:
    632:{id: "632",  pid: "2993", ESID: "9154", lb1: "Undddd", lb2: "219"}
    877:{id: "877",  pid: "2993", ESID: "9154", lb1: "Pcddd", lb2: "29"}
    654:{id: "654",  pid: "2993", ESID: "9154", lb1: "kukuu", lb2: "246"}]

在视图文件中

 <div ng-if="item.pmptnk.length > 0">
    <ui-select ng-model="item.pmpo" click-out-side="closeThis($event)">
    <ui-select-match placeholder="Select " search-placeholder="Filter Tanks" 
    uib-tooltip="{{item.pmpo > 0 ? $select.selected.lb1 : 'Select Tank'}}" tab-select="true">
         <span ng-bind="$select.selected.lb1"></span>
    </ui-select-match>
    <ui-select-choices repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">
        <span ng-bind="obj.lb1"></span>
    </ui-select-choices>
    <ui-select-no-choice>
      No results matched "{{$select.search}}"
    </ui-select-no-choice>
    </ui-select>

</div>

Answer 1

我处理了您的代码。我以不同的方式进行了尝试。 下面是我的代码sn-p：

<div ng-if="item.pmptnk.length > 0">
        <ui-select ng-model="item.selected" click-out-side="closeThis($event)">
           <ui-select-match placeholder="Select " search-placeholder="Filter Tanks" uib-tooltip="{{item.pmpo > 0 ? $select.selected.lb1 : 'Select Tank'}}" tab-select="true">
              <span ng-bind="$select.selected.lb1"></span>
           </ui-select-match>
           <ui-select-choices repeat="obj.tid as obj in (item.pmptnk)">
              <span ng-bind="obj.lb1"></span>
           </ui-select-choices>
       <ui-select-no-choice>
            No results matched "{{$select.search}}"
       </ui-select-no-choice>
   </ui-select>

我改变了我的模型如下：

$scope.item = {};
    $scope.item.pmpo=877;
    $scope.item.pmptnk=[
    {id: "632",  pid: "2993", ESID: "9154", lb1: "Undddd", lb2: "219"},
    {id: "877",  pid: "2993", ESID: "9154", lb1: "Pcddd", lb2: "29"},
    { id: "654", pid: "2993", ESID: "9154", lb1: "kukuu", lb2: "246" }];
    for (var i = 0 ; i < $scope.item.pmptnk.length; i++) {
        if ($scope.item.pmptnk[i].id == $scope.item.pmpo) {
            $scope.item.selected = $scope.item.pmptnk[i].tid;
            break;
        }
    }

这对我来说很好。

Answer 2

根据docs of ui-select-choices，repeat 属性

指定要作为选项提供的项目列表。语法相似 到 ngRepeat。

并根据ng-repeat doc

可以让 ngRepeat 迭代一个 使用以下语法的对象：

<div ng-repeat="(key, value) in myObj"> ... </div>

因此，我们可以得出结论，您应该更改您的语法：

<ui-select-choices repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">

到此：

<ui-select-choices repeat="(key, value) in (item.pmptnk[item.pmpo])">

其中value 将是877、2993 等等，key 将是id、pid 等等。

Answer 3

不应该是 ng-repeat 而不是只是重复吗？

 <ui-select-choices repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">

将此行更改为以下行

<ui-select-choices ng-repeat="obj.tid as obj in (item.pmptnk[item.pmpo])">

希望能解决这个问题。