如何从给定对象以指定方式获取构造对象答案

【问题标题】：how to get construct object in specified manner from given object如何从给定对象以指定方式获取构造对象
【发布时间】：2018-08-23 09:40:40
【问题描述】：

我在以所需格式构造 object 时遇到问题。

我想以这种方式获取对象

{"pendrive":['went to each object and picked "TEST_HOME" value'],"minichip":['went to each object and picked "TEST_PROXY" value']}

上述array的值必须从每个object中收集，方法是转到mount_status然后key，对于示例 TEST_PROXY,TEST_HOME,TEST_ARCHIVE ,TEST_TARGET

所需的输出： {"pendrive":["error","na","error","ok","na","na"]} 用于键 "TEST_HOME" 其他人相同

这是我尝试过的：

  var nodeSum = {};
var nodeStatus = {
  "node_stats": {
    "pendrive": {
      "mount_status": {
        "TEST_PROXY": "error",
        "TEST_TARGET": "error",
        "TEST_ARCHIVE": "error",
        "TEST_HOME": "error"
      }
    },
    "minichip": {
      "mount_status": {
        "TEST_PROXY": "na",
        "TEST_TARGET": "na",
        "TEST_ARCHIVE": "na",
        "TEST_HOME": "na"
      }
    },
    "simcard": {
      "mount_status": {
        "TEST_HOME": "error",
        "TEST_TARGET": "error",
        "TEST_ARCHIVE": "error",
        "TEST_PROXY": "error"
      }
    },
    "hostname": [
      "nikola",
      "goldplus",
      "pendrive",
      "simcard",
      "airtel",
      "minichip",
      "voda"
    ],
    "airtel": {
      "mount_status": {
        "TEST_PROXY": "ok",
        "TEST_TARGET": "ok",
        "TEST_ARCHIVE": "ok",
        "TEST_HOME": "ok"
      }
    },
    "voda": {
      "mount_status": {
        "TEST_HOME": "na",
        "TEST_TARGET": "na",
        "TEST_ARCHIVE": "na",
        "TEST_PROXY": "na"
      }
    },
    "nikola": {
      "mount_status": {
        "TEST_HOME": "na",
        "TEST_ARCHIVE": "na",
        "TEST_TARGET": "na",
        "TEST_PROXY": "na"
      }
    }
  }
}


console.log(nodeStatus);

var hostNames = nodeStatus["node_stats"]["hostname"];

for(var i = 0; i<hostNames.length;i++){

  if(nodeStatus["node_stats"][hostNames[i]]){
    eachNode = nodeStatus["node_stats"][hostNames[i]];
    console.log(eachNode);
  }
  //nodeSum[hostNames[i]] = eachNode["mount_status"][Object.keys(eachNode["mount_status"])];
  if(eachNode){
    if(eachNode.hasOwnProperty("mount_status")){
      if(i <= 1)
        var allBins = Object.keys(eachNode["mount_status"]);
        console.log('all keys',allBins);
        console.log(nodeStatus["node_stats"][hostNames[i]][allBins[i]]);
        console.log(Object.values(eachNode["mount_status"]));

        var binStatusArray = Object.values(eachNode["mount_status"]);
        nodeSum[allBins[i]] = eachNode["mount_status"][allBins[i]];
      }
    }         
  }
  console.log('results',nodeSum);
}

【问题讨论】：

{"pendrive":["error","na","error","ok","na","na"]} 只有一个TEST_HOME 是它的孩子，你确定不想要node_stats 吗？
你的缩进让这段代码很难阅读。

标签： javascript jquery node.js

【解决方案1】：

如果可能，我会更改以下内容

const nodeStatus = {
  "hostname": [
      "nikola",
      "goldplus",
      "pendrive",
      "simcard",
      "airtel",
      "minichip",
      "voda"
  ],
  "node_stats": {
    "pendrive": {
      "mount_status": {
        "TEST_PROXY": "error",
        "TEST_TARGET": "error",
        "TEST_ARCHIVE": "error",
        "TEST_HOME": "error"
      }
    },
    "minichip": {
      "mount_status": {
        "TEST_PROXY": "na",
        "TEST_TARGET": "na",
        "TEST_ARCHIVE": "na",
        "TEST_HOME": "na"
      }
    },
    "simcard": {
      "mount_status": {
        "TEST_HOME": "error",
        "TEST_TARGET": "error",
        "TEST_ARCHIVE": "error",
        "TEST_PROXY": "error"
      }
    },
    "airtel": {
      "mount_status": {
        "TEST_PROXY": "ok",
        "TEST_TARGET": "ok",
        "TEST_ARCHIVE": "ok",
        "TEST_HOME": "ok"
      }
    },
    "voda": {
      "mount_status": {
        "TEST_HOME": "na",
        "TEST_TARGET": "na",
        "TEST_ARCHIVE": "na",
        "TEST_PROXY": "na"
      }
    },
    "nikola": {
      "mount_status": {
        "TEST_HOME": "na",
        "TEST_ARCHIVE": "na",
        "TEST_TARGET": "na",
        "TEST_PROXY": "na"
      }
    }
  }
}

const testHome = nodeStatus.hostname.map(name => nodeStatus["node_stats"][name] 
  ? nodeStatus["node_stats"][name]["mount_status"]["TEST_HOME"] 
  : undefined);

// ["nikola", "goldplus", "pendrive", "simcard", "airtel", "minichip", "voda"]
console.log(testHome) //["na", undefined, "error", "error", "ok", "na", "na"]

主机名与所有其他主机名不同，因此您希望将其从node_stats 中取出。结果的顺序将与hostname的顺序相同

如果您不想要未定义的，那么您可以使用Array.reduce，但副作用是Array 的顺序无法预测。

【讨论】：

【解决方案2】：

您可以对每种类型的项目和属性名称使用对象查找。然后使用Object.keys()遍历lookup的每个key，array#reduce每个key对应lookup属性的所有值，并使用array#reduce每个对象的所有值创建一个数组。

var nodeStatus = { "node_stats": { "pendrive": { "mount_status": { "TEST_PROXY": "error", "TEST_TARGET": "error", "TEST_ARCHIVE": "error", "TEST_HOME": "error" } }, "minichip": { "mount_status": { "TEST_PROXY": "na", "TEST_TARGET": "na", "TEST_ARCHIVE":"na", "TEST_HOME": "na" } }, "simcard": { "mount_status":{ "TEST_HOME": "error", "TEST_TARGET": "error", "TEST_ARCHIVE": "error", "TEST_PROXY": "error" } }, "hostname": [ "nikola", "goldplus", "pendrive", "simcard", "airtel", "minichip", "voda" ], "airtel":{ "mount_status": { "TEST_PROXY": "ok", "TEST_TARGET": "ok", "TEST_ARCHIVE": "ok", "TEST_HOME": "ok" } }, "voda": { "mount_status": { "TEST_HOME": "na", "TEST_TARGET": "na", "TEST_ARCHIVE": "na", "TEST_PROXY": "na" } }, "nikola": { "mount_status": { "TEST_HOME":"na", "TEST_ARCHIVE": "na", "TEST_TARGET": "na", "TEST_PROXY": "na" } } } },
    lookup = {pendrive: 'TEST_HOME', minichip: 'TEST_PROXY'}
    result = Object.keys(lookup).reduce((o,k) => {
      o[k] =  Object.keys(nodeStatus.node_stats).reduce((r,key) => {
      if('mount_status' in nodeStatus.node_stats[key])
          r.push(nodeStatus.node_stats[key].mount_status[lookup[k]]);
      return r;
    },[]);
    return o;
   },{});
console.log(result);

【讨论】：

【解决方案3】：

如果你想要这样的输出：

TEST_ARCHIVE的键

{error: ["pendrive", "simcard"], na: ["minichip", "voda", "nikola"], ok: ["airtel"]}

使用这个：

function getNestedValuesForKey(key_name){
	var hosts	=	nodeStatus.node_stats;
	var return_values	=	{};
	for( var _hostname in hosts ){
		var _host	=	hosts[_hostname];
		if( _host.mount_status ){
			var _status	=	_host.mount_status[key_name];
			if( !return_values[_status] ){
				return_values[_status]	=	new Array;
			}//if
			return_values[_status].push(_hostname);
		}//if
	}//for
	return return_values
}//function

var nodeStatus = {"node_stats":{"pendrive":{"mount_status":{"TEST_PROXY":"error","TEST_TARGET":"error","TEST_ARCHIVE":"error","TEST_HOME":"error"}},"minichip":{"mount_status":{"TEST_PROXY":"na","TEST_TARGET":"na","TEST_ARCHIVE":"na","TEST_HOME":"na"}},"simcard":{"mount_status":{"TEST_HOME":"error","TEST_TARGET":"error","TEST_ARCHIVE":"error","TEST_PROXY":"error"}},"hostname":["nikola","goldplus","pendrive","simcard","airtel","minichip","voda"],"airtel":{"mount_status":{"TEST_PROXY":"ok","TEST_TARGET":"ok","TEST_ARCHIVE":"ok","TEST_HOME":"ok"}},"voda":{"mount_status":{"TEST_HOME":"na","TEST_TARGET":"na","TEST_ARCHIVE":"na","TEST_PROXY":"na"}},"nikola":{"mount_status":{"TEST_HOME":"na","TEST_ARCHIVE":"na","TEST_TARGET":"na","TEST_PROXY":"na"}}}};

console.log( getNestedValuesForKey('TEST_ARCHIVE') );

【讨论】：

【解决方案4】：

目前还不清楚你想要什么。一种可能性是，当您在寻找 TEST_PROXY 时，您应该得到

["na", undefined, "error", "error", "ok", "na", "na"]

（undefined 是因为hostname 包含“goldplus”，而node_stats 中不包含。）

如果这是您想要的，那么这应该可以：

const nodeStatus = {"node_stats": {"airtel": {"mount_status": {"TEST_ARCHIVE": "ok", "TEST_HOME": "ok", "TEST_PROXY": "ok", "TEST_TARGET": "ok"}}, "hostname": ["nikola", "goldplus", "pendrive", "simcard", "airtel", "minichip", "voda"], "minichip": {"mount_status": {"TEST_ARCHIVE": "na", "TEST_HOME": "na", "TEST_PROXY": "na", "TEST_TARGET": "na"}}, "nikola": {"mount_status": {"TEST_ARCHIVE": "na", "TEST_HOME": "na", "TEST_PROXY": "na", "TEST_TARGET": "na"}}, "pendrive": {"mount_status": {"TEST_ARCHIVE": "error", "TEST_HOME": "error", "TEST_PROXY": "error", "TEST_TARGET": "error"}}, "simcard": {"mount_status": {"TEST_ARCHIVE": "error", "TEST_HOME": "error", "TEST_PROXY": "error", "TEST_TARGET": "error"}}, "voda": {"mount_status": {"TEST_ARCHIVE": "na", "TEST_HOME": "na", "TEST_PROXY": "na", "TEST_TARGET": "na"}}}}

const nodeSum = (key, nodes) => nodes.node_stats.hostname
    .map(hostname => (nodes.node_stats[hostname] || {mount_status: {}}).mount_status[key])


console.log(nodeSum("TEST_PROXY", nodeStatus))

但那是相当不清楚的格式。相反，如果你想要这样的东西：

{
  "nikola":"na",
  "pendrive":"error",
  "simcard":"error",
  "airtel":"ok",
  "minichip":"na",
  "voda":"na"
}

然后你可以像这样修改函数：

const nodeStatus = {"node_stats": {"airtel": {"mount_status": {"TEST_ARCHIVE": "ok", "TEST_HOME": "ok", "TEST_PROXY": "ok", "TEST_TARGET": "ok"}}, "hostname": ["nikola", "goldplus", "pendrive", "simcard", "airtel", "minichip", "voda"], "minichip": {"mount_status": {"TEST_ARCHIVE": "na", "TEST_HOME": "na", "TEST_PROXY": "na", "TEST_TARGET": "na"}}, "nikola": {"mount_status": {"TEST_ARCHIVE": "na", "TEST_HOME": "na", "TEST_PROXY": "na", "TEST_TARGET": "na"}}, "pendrive": {"mount_status": {"TEST_ARCHIVE": "error", "TEST_HOME": "error", "TEST_PROXY": "error", "TEST_TARGET": "error"}}, "simcard": {"mount_status": {"TEST_ARCHIVE": "error", "TEST_HOME": "error", "TEST_PROXY": "error", "TEST_TARGET": "error"}}, "voda": {"mount_status": {"TEST_ARCHIVE": "na", "TEST_HOME": "na", "TEST_PROXY": "na", "TEST_TARGET": "na"}}}}

const nodeSum = (key, nodes) => nodes.node_stats.hostname
    .map(hostname => ({[hostname]: (nodes.node_stats[hostname] || {mount_status: {}})
                                   .mount_status[key]}))
    .reduce((a, b) => Object.assign(a, b), {})

console.log(nodeSum("TEST_HOME", nodeStatus))

如果您可以保证在您的示例中没有像“goldplus”这样的情况，其中主机名包含在主机名列表中但不包含在node_stats 中，那么您可以将这些函数简化为

const nodeSum = (key, nodes) => nodes.node_stats.hostname
    .map(hostname => nodes.node_stats[hostname].mount_status[key])

和

const nodeSum = (key, nodes) => nodes.node_stats.hostname
    .map(hostname => ({[hostname]: nodes.node_stats[hostname].mount_status[key]}))
    .reduce((a, b) => Object.assign(a, b), {})

最后，在一次迭代中完成后者可能会更干净，如下所示：

const nodeSum = (key, nodes) => nodes.node_stats.hostname
    .reduce((acc, hostname) => {
      acc[hostname] = nodes.node_stats[hostname].mount_status[key]
      return acc
    }, {})

nodeSum 是这个函数的一个可怕名称，但您似乎正在使用该名称更新一个变量来保存您的输出。对于实际代码，我会将其更改为更明确的内容。

【讨论】：