为什么忽略此函数定义？ [关闭]

Question

谁能弄清楚我为什么会得到

TypeError: getStatusCode(...) is not a function

我什么时候做？

const getStatusCode = require('./getStatusCode')
tmpStatus = await getStatusCode({url: url, timeOut: to, maxRedirects: mr})
(tmpStatus === alert['Check']['Status_code'] ) ? isOk = 1 : isOk = 0

如果我删除最后一行，我检查tmpStatus 中的值，问题就会出现。

getStatusCode.js

const axios = require('axios')
const qs = require('qs')

module.exports = async function(options) => {
  options              = options || {}
  options.url          = options.url || {}
  options.string       = options.string || null
  options.timeOut      = options.timeOut || 1000
  options.maxRedirects = options.maxRedirects || 0

  try {
    const response = await axios.get(options.url, {
      timeout: options.timeout,
      maxRedirects: options.maxRedirects,
      validateStatus: null,
      transformResponse: [function (data) {
        return data.search(options.string)
  }],
    })
    return await response.data
  } catch (error) {
    return -1
  }
}

Answer 1

尝试删除=>。

const axios = require('axios')
const qs = require('qs')

module.exports = async function(options) {
  options              = options || {}
  options.url          = options.url || {}
  options.string       = options.string || null
  options.timeOut      = options.timeOut || 1000
  options.maxRedirects = options.maxRedirects || 0

  try {
    const response = await axios.get(options.url, {
      timeout: options.timeout,
      maxRedirects: options.maxRedirects,
      validateStatus: null,
      transformResponse: [function (data) {
        return data.search(options.string)
  }],
    })
    return await response.data
  } catch (error) {
    return -1
  }
}

Answer 2

错误是因为您没有在分配行的末尾放置;。所以它被解释为好像你写的一样

tmpStatus = await getStatusCode({url: url, timeOut: to, maxRedirects: mr})(tmpStatus === alert['Check']['Status_code'] ) 
    ? isOk = 1 : isOk = 0;

这是试图使用getStatusCode() 的结果作为函数，tmpStatus === alert['Check']['Status_code'] 的值作为其参数。

见What are the rules for JavaScript's automatic semicolon insertion (ASI)?

我建议您始终使用分号，而不是依赖于 ASI。