【问题标题】:Beginner async/await question for api requestsapi请求的初学者异步/等待问题
【发布时间】:2020-12-04 06:06:06
【问题描述】:

我想加快一些 API 请求的速度...为此,我试图弄清楚如何去做并复制一些运行的代码,但是当我尝试自己的代码时,它不再是异步的。也许有人发现失败了?

复制代码(从stackoverflow猜测):

#!/usr/bin/env python3
import asyncio

@asyncio.coroutine
def func_normal():
    print('A')
    yield from asyncio.sleep(5)
    print('B')
    return 'saad'

@asyncio.coroutine
def func_infinite():
    for i in range(10):
        print("--%d" % i)
    return 'saad2'

loop = asyncio.get_event_loop()
tasks = func_normal(), func_infinite()
a, b = loop.run_until_complete(asyncio.gather(*tasks))
print("func_normal()={a}, func_infinite()={b}".format(**vars()))
loop.close()

我的“自己的”代码(我需要在最后返回一个列表并合并所有函数的结果):

import asyncio
import time


@asyncio.coroutine
def say_after(start,count,say,yep=True):
    retl = []
    if yep:
        time.sleep(5)
    for x in range(start,count):
        retl.append(x)
        print(say)
    return retl


def main():
    print(f"started at {time.strftime('%X')}")
        
    loop = asyncio.get_event_loop()
    tasks = say_after(10,20,"a"), say_after(20,30,"b",False)
    a, b = loop.run_until_complete(asyncio.gather(*tasks))
    print("func_normal()={a}, func_infinite()={b}".format(**vars()))
    loop.close()
    c =  a + b

    #print(c)
    print(f"finished at {time.strftime('%X')}")

main()

或者我完全错了,应该用多线程解决这个问题?对于返回我需要合并的列表的 API 请求,最好的方法是什么?

【问题讨论】:

  • 您的代码需要一个或多个点将执行交回事件循环以异步执行其他内容。这就是第一个代码中的“yield from”的用途(在较新的 Python 版本中为“await”)。

标签: python multithreading async-await python-asyncio


【解决方案1】:

为每个需要改进的部分添加了评论。删除了一些简单的代码。

事实上,我没有发现使用包裹在协程中的 range() 和使用 async def 有任何性能提升,可能值得进行更繁重的操作。

import asyncio
import time

# @asyncio.coroutine IS DEPRECATED since python 3.8
@asyncio.coroutine
def say_after(wait=True):
    result = []

    if wait:
        print("I'm sleeping!")
        time.sleep(5)
        print("'morning!")
        # This BLOCKs thread, but release GIL so other thread can run.
        # But asyncio runs in ONE thread, so this still harms simultaneity.

    # normal for is BLOCKING operation.
    for i in range(5):
        result.append(i)
        print(i, end='')
    print()

    return result


def main():
    start = time.time()

    # Loop argument will be DEPRECATED from python 3.10
    # Make main() as coroutine, then use asyncio.run(main()).
    # It will be in asyncio Event loop, without explicitly passing Loop.
    loop = asyncio.get_event_loop()
    tasks = say_after(), say_after(False)

    # As we will use asyncio.run(main()) from now on, this should be await-ed.
    a, b = loop.run_until_complete(asyncio.gather(*tasks))

    print(f"Took {time.time() - start:5f}")

    loop.close()


main()

更好的方法:

import asyncio
import time


async def say_after(wait=True):
    result = []

    if wait:
        print("I'm sleeping!")
        await asyncio.sleep(2)  # 'await' a coroutine version of it instead.
        print("'morning!")

    # wrap iterator in generator - or coroutine
    async def asynchronous_range(end):
        for _i in range(end):
            yield _i

    # use it with async for
    async for i in asynchronous_range(5):
        result.append(i)
        print(i, end='')
    print()

    return result


async def main():
    start = time.time()

    tasks = say_after(), say_after(False)
    a, b = await asyncio.gather(*tasks)

    print(f"Took {time.time() - start:5f}")


asyncio.run(main())


结果

您的代码:

DeprecationWarning: "@coroutine" decorator is deprecated since Python 3.8, use "async def" instead
  def say_after(wait=True):
I'm sleeping!
'morning!
01234
01234
Took 5.003802

更好的异步代码:

I'm sleeping!
01234
'morning!
01234
Took 2.013863

请注意,固定代码现在在其他任务处于休眠状态时完成其工作。

【讨论】:

  • 也许在协程中包装 for 根本不值得 - 我会检查一下。
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