无法让我在嵌套循环中创建的菜单正常运行

Question

我正在尝试创建需要使用大量菜单的程序（作为初学者，这些东西真的开始让我不知所措，但它是为我的班级设计的）。这是我目前所拥有的：

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;


public class GroupUs {

public static void main(String[] args) {


    String fileName = "CompConClass.txt"; //File includes class roster  

    System.out.println("Hello, would you like to access the class that you have on file or would you like to create a new class?");

    int choice = mainMenu();
    int choice2 = subMenu();

    while (choice != 0) {
        if (choice == 1) {  

            subMenu(); //calls subMenu method

        if (choice2 == 1 ) {

            try {
                BufferedReader br = new BufferedReader(new FileReader(fileName));

                String line = null; //create a line variable 
                while ((line = br.readLine()) != null) { //this will read the file line by line

                    System.out.println(line); //displays every line
                }

              } catch (FileNotFoundException ex) {
                  ex.printStackTrace();
              } catch (IOException ex) {
                  ex.printStackTrace();
              }


        }


        } else if (choice == 2) {
            System.out.println("test");
        }

        choice = mainMenu();

        }

    }        

    public static int mainMenu() {
        Scanner scan = new Scanner(System.in);  // Reading from System.in
        System.out.println( "Press 0 to quit.\n"
                + "Press 1 to access the class that you have on file.\n"
                + "Press 2 to create a new class.\n"
                );
        return scan.nextInt(); // Scans the next token of the input as an int.
    }

    public static int subMenu() {
        Scanner scan = new Scanner(System.in);  // This method will give the teacher the ability to view the roster from the file or add students on to that file
        System.out.println( "What would you like to do to the class on file?\n"
                + "Press 1 to view the students.\n"
                + "Press 2 to add another student.\n"
                + "Press 3 to remove a student."
                );
        return scan.nextInt(); // Scans the next token of the input as an int.
    }      

}

具体来说，我在这部分代码中遇到了问题

  if (choice == 1) {  

        subMenu(); //calls subMenu method

    if (choice2 == 1 ) {

        try {
            BufferedReader br = new BufferedReader(new FileReader(fileName));

            String line = null; //create a line variable 
            while ((line = br.readLine()) != null) { //this will read the file line by line

                System.out.println(line); //displays every line
            }

          } catch (FileNotFoundException ex) {
              ex.printStackTrace();
          } catch (IOException ex) {
              ex.printStackTrace();
          }

发生的情况是，程序最初通过向用户展示我创建的第一个 mainMenu 方法开始良好。当我输入数字 1 以打开我的 subMenu 方法时，它也可以正常工作。但是，当我在 subMenu 一侧再次按 1（这次是显示文件中的名单）时，它只是再次打印出 subMenu。我再次按 1，然后它会根据需要向我显示名册。我不知道为什么我不能让它在第一次显示。

Answer 1

int choice2 = subMenu();

while (choice != 0) {
    if (choice == 1) {  

        subMenu(); //calls subMenu method

您调用了两次subMenu() 方法，这就是它运行两次的原因。