不需要重复数据给我，在这种情况下请帮助我：身份证重复，我需要如下所述[关闭]

Question

请找到以下数据。

no need duplicate data to me, Please help me in this case:
Id's are Duplicated, i need output without duplicates:

Actual Data:
(9) [{…}, {…}, {…}, {…}, {…}, {…}]
    0: {Id: 0, Specialization: "General", Description: "General", IsActive: true},
    1: {Id: 1, Specialization: "General", Description: "General", IsActive: true},
    2: {Id: 2, Specialization: "General", Description: "General", IsActive: true},
    3: {Id: 3, Specialization: "General", Description: "General", IsActive: true},
    4: {Id: 4, Specialization: "General", Description: "General", IsActive: true},
    5: {Id: 1, Specialization: "General", Description: "General", IsActive: true},
    6: {Id: 2, Specialization: "General", Description: "General", IsActive: true},
    7: {Id: 3, Specialization: "General", Description: "General", IsActive: true},
    8: {Id: 4, Specialization: "General", Description: "General", IsActive: true}
    

I need Output Like this below:
(5) [{…}, {…}, {…}, {…}, {…}, {…}]
    0: {Id: 0, Specialization: "General", Description: "General", IsActive: true},
    1: {Id: 1, Specialization: "General", Description: "General", IsActive: true},
    2: {Id: 2, Specialization: "General", Description: "General", IsActive: true},
    3: {Id: 3, Specialization: "General", Description: "General", IsActive: true},
    4: {Id: 4, Specialization: "General", Description: "General", IsActive: true}

我需要如上的输出 我需要如上的输出 我需要如上的输出 我需要如上的输出

Answer 1

您可以使用forEach 进行迭代并使用some 检查更新数组是否具有现有Id

const inputData = [ {Id: 0, Specialization: "General", Description: "General", IsActive: true},
    {Id: 1, Specialization: "General", Description: "General", IsActive: true},
    {Id: 2, Specialization: "General", Description: "General", IsActive: true},
    {Id: 3, Specialization: "General", Description: "General", IsActive: true},
    {Id: 4, Specialization: "General", Description: "General", IsActive: true},
    {Id: 1, Specialization: "General", Description: "General", IsActive: true},
    {Id: 2, Specialization: "General", Description: "General", IsActive: true},
    {Id: 3, Specialization: "General", Description: "General", IsActive: true},
    {Id: 4, Specialization: "General", Description: "General", IsActive: true}]

let output = [];
    inputData.forEach(val => {
 var isExist = output.some(data => data.Id === val.Id);
 if(!isExist) output.push(val)
})

console.log(output)

Answer 2

如果您只想按Id 过滤，请使用reduce 和Object.values：

const output = Object.values(data.reduce((a, { Id, ...o }) => {
  a[Id] = a[Id] || { Id, ...o };
  return a;
}, {}));

const data = [{Id:0,Specialization:"General",Description:"General",IsActive:true},{Id:1,Specialization:"General",Description:"General",IsActive:true},{Id:2,Specialization:"General",Description:"General",IsActive:true},{Id:3,Specialization:"General",Description:"General",IsActive:true},{Id:4,Specialization:"General",Description:"General",IsActive:true},{Id:1,Specialization:"General",Description:"General",IsActive:true},{Id:2,Specialization:"General",Description:"General",IsActive:true},{Id:3,Specialization:"General",Description:"General",IsActive:true},{Id:4,Specialization:"General",Description:"General",IsActive:true}];

const output = Object.values(data.reduce((a, { Id, ...o }) => {
  a[Id] = a[Id] || { Id, ...o };
  return a;
}, {}));

console.log(output);

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Answer 3

使用下面的代码：

let uniqueArray= Array.from(duplicateArray.reduce((m, t) => m.set(t.Id, t), new Map()).values());
console.log(uniqueArray);