如何迭代json对象？答案

【问题标题】：How to iterate json object?如何迭代json对象？
【发布时间】：2019-07-21 03:02:54
【问题描述】：

我从外部API(external API) 获得以下值。我认为这是JSON 对象。如何以角度打印此值？

    {
    "job_details": {
        "job_title": "Cook",
        "company_email": "suryaadisiva@gmail.com",
        "industry": "Advertisement",
        "phone_no": "9746448899",
        "days_to_join_id": "2",
        "days_to_join": "Within a week",
        "participatestatus": "0",
        "job_type_name": "Full Time",
        "Qualficationprofileflag": "1",
        "jobview_count": "1",
        "company_id": "440",
        "job_add_date": "2019-02-26 09:33:36",
        "minimum_qual": "10th/SSLC",
        "Skills": "Chinese",
        "jobgender": "Female",
        "date_diff": 1,
        "experience": "2 - 3 years",
        "salary": "Rs 10,000 - 15,000"
         },
    "jobtoshowflag": "1",
    "jobdeleted": 0
}

以上是来自外部API的格式。用 angular 打印这个的 html 语法是什么？

【问题讨论】：

您的标题与您在帖子中要求的完全不同。你想问什么，如何迭代json或如何在html中显示或两者兼而有之？

标签： html angular

【解决方案1】：

将回复保存在variable 中，比如data

data = {
    "job_details": {
        "job_title": "Cook",
        "company_email": "suryaadisiva@gmail.com",
        "industry": "Advertisement",
        "phone_no": "9746448899",
        "days_to_join_id": "2",
        "days_to_join": "Within a week",
        "participatestatus": "0",
        "job_type_name": "Full Time",
        "Qualficationprofileflag": "1",
        "jobview_count": "1",
        "company_id": "440",
        "job_add_date": "2019-02-26 09:33:36",
        "minimum_qual": "10th/SSLC",
        "Skills": "Chinese",
        "jobgender": "Female",
        "date_diff": 1,
        "experience": "2 - 3 years",
        "salary": "Rs 10,000 - 15,000"
         },
    "jobtoshowflag": "1",
    "jobdeleted": 0
    }

HTML

<h1>{{data.jobtoshowflag}}</h1>
<h1>{{data.job_details.job_title}}</h1>

【讨论】：