【发布时间】:2021-04-15 07:38:29
【问题描述】:
我正在使用 Jquery 和 ajax 编写应用程序。响应正在加载到 HTML,然后消失。
HTML
<figure class="card card--normal" id="firstResponse">
<div class="card__image-container">
<img id="#pokemon1Image" src="" alt="card" class="card__image">
</div>
<figcaption class="card__caption">
<h1 id="pokemon1Name"></h1>
<h3 class="card__type" id="pokemon1Type"></h3>
<table class="card__stats">
<tbody><tr>
<th>HP</th>
<td id="Pokemon1Exp"></td>
</tr>
<tr>
<th>Attack</th>
<td id='pokemon1Attack'></td>
</tr>
<tr>
<th>Defense</th>
<td id="pokemon1Defense"></td>
</tr>
<tr>
<th>Special Attack</th>
<td></td>
</tr>
<tr>
<th>Special Defense</th>
<td> <p id="pokemon1Defense"></p></td>
回应
.then(function (response) {
var pokeID = response.id;
var imageURL =
$("#pokemon1Image").attr("src", imageURL);
$("#pokemon1Name").html(nameOfPokemon);
// $("#pokemon1Type").text(type + " type");
var attack =response.stats[1].base_stat
// $("#pokemon1Attack").text(attack);
// $("#pokemon1Defense").text(response.stats[2].base_stat);
$("#pokemon1Speed").html(response.stats[5].base_stat);
$("#pokemon1Exp").html(response.base_experience);
$("#Ability").html(response.abilities.ability[0])
我觉得我整天都在这样做。有谁知道为什么会这样,你能帮忙吗?
谢谢
【问题讨论】:
-
示例代码似乎不完整,例如
var imageURL =未分配任何值。如果您能分享一个小例子来说明您的问题所在,我们可以为您提供更好的帮助。 -
啊哎呀不,不是这样。我已经剪切和粘贴了一些东西,因为 stackoverlow 不允许你添加一堆代码。不过这个是需要的
-
$(document).ready(function() { $("#search-btn").on("click", function () { // event.preventDefault(); var userInput = $("#input").val(); var search = userInput.toLowerCase(); $("#input").val(""); // var pokemon = userInput.toLower pokemonOne(search); }) ; function pokemonOne(search){ var queryURL = "pokeapi.co/api/v2/pokemon" + search; $.ajax({ url: queryURL, method: "GET",
-
数据类型:“json”,
-
}).then(function (response) { var pokeID = response.id; var imageURL = "raw.githubusercontent.com/PokeAPI/sprites/master/sprites/…" + pokeID + ".png"; var nameOfPokemon = response.name; $( "#pokemon1Image").attr("src", imageURL); $("#pokemon1Name").html(nameOfPokemon); // $("#pokemon1Type").text(type + "type");