405 Method Not Allowed：请求的 URL 不允许该方法答案

【问题标题】：405 Method Not Allowed: The method is not allowed for the requested URL405 Method Not Allowed：请求的 URL 不允许该方法
【发布时间】：2021-02-01 07:58:32
【问题描述】：

我一直在开发一个系统，但我最近无法调试为什么会出现此错误不允许的方法请求的 URL 不允许该方法。我一直在开发一个系统我认为问题与不允许发布功能并被某些东西打断有关，请帮助我谢谢。代码：

蟒蛇

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

from flask import Flask, render_template, request
app = Flask(__name__)

@app.route('/')
def student():
    return render_template('index.html')

@app.route('/result',methods = ['POST', 'GET'])
def result():
    if request.method == 'POST':
        result = request.form['name']
        print(result)
        return "thank you for filling out this form"

if __name__ == '__main__':
    app.run(debug = True)
file_object = open('transferfile.txt', 'a+')
name = "Gabriel"
age = "12"
gender = "male"
file_object.write(name)
file_object.write(" ")
data = file_object.read(100)
file_object.write(age)
file_object.write(" ")
file_object.write(gender)
file_object.close()

html

<!DOCTYPE html>
<html lang="en">
<head>
    <link rel="stylesheet" href="style.css">
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>venuefast</title>
</head>
<body>
    <form class="logo" action="." method="post">fastvenue<br>
        <hr>
        <input type ="text" name="name" placeholder="name">
        <br>
        <button type="submit" value="submit">Submit</button>
    </form> 
</body>
</html>

【问题讨论】：

标签： python html forms flask

【解决方案1】：

由于学生函数在 index.html 中呈现表单，因此只有学生函数接受 POST 请求才有意义：

from flask import Flask, render_template, request
app = Flask(__name__)

@app.route('/',methods = ['POST', 'GET'])
def student():
    if request.method == 'POST':
        name = request.form['name']
        return f"thank you for filling out this form {name}!"
    return render_template('index.html')


@app.route('/result')
def result():
    return 'this function does nothing yet'

if __name__ == '__main__':
    app.run(debug = True)

另一种选择，如果您打算将 student 用于其他用途，您可以让 result 函数呈现 index.html 并使其接受 POST 请求：


from flask import Flask, render_template, request
app = Flask(__name__)

@app.route('/')
def student():
    return 'this function does nothing yet'


@app.route('/result',methods = ['POST', 'GET'])
def result():
    if request.method == 'POST':
        name = request.form['name']
        return f"thank you for filling out this form {name}!"
    return render_template('index.html')

if __name__ == '__main__':
    app.run(debug = True)

【讨论】：

【解决方案2】：

在 HTML 中试试这个

<html lang="en">
<head>
    <link rel="stylesheet" href="style.css">
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>venuefast</title>
</head>
<body>
    <form class="logo" action="/result" method="POST">
        <p>fastvenue</p>
        <br>
        <hr>
        <input type ="text" name="name" placeholder="name">
        <br>
        <button type="submit" value="submit">Submit</button>
    </form> 
</body>
</html>

【讨论】：