我为此写了一个解决方法。
小心点,很脏;)
步骤:
- 您需要创建一个包含表单的 html 文件
- 向其中添加与您需要传递给您的 url 的值相对应的输入字段
- 将此文件添加到您的资产文件夹中
- 关于安卓代码:
示例:
这是我在 assets 文件夹中名为 form_template.html 的 html 文件:
<html>
<script>
function submitForm() {
document.getElementById("form").submit()
}
</script>
<body onload="submitForm()">
<form id="form" action="{{url}}" method="{{method}}" enctype="{{enctype}}">
{{fields}}
</form>
</body>
</html>
这就是我动态传递 url 和值的方式
Map<String, String> values = ImmutableMap.of(
"fooKey", "fooValue", // whatever you
"barKey", "barValue" // need here
);
try {
File redirect = new File(activity.getExternalCacheDir(), "redirect.html");
// To get string from input stream look at here https://stackoverflow.com/a/16110044/2124387
String templateString = getStringFromInputStream(activity.getAssets().open("form_template.html"));
List<String> inputFields = new ArrayList<>();
for (String key : values.keySet()) {
inputFields.add(String.format("<input type=\"hidden\" name=\"%s\" value=\"%s\" />", key, values.get(key)));
}
templateString = templateString.replace("{{url}}", url);
templateString = templateString.replace("{{method}}", method); // eg. "POST"
templateString = templateString.replace("{{enctype}}", encodeType); // eg. "application/x-www-form-urlencoded"
templateString = templateString.replace("{{fields}}", StringUtil.join("\n", inputFields));
FileOutputStream fileOutputStream = new FileOutputStream(redirect);
fileOutputStream.write(templateString.getBytes());
Uri uri = FileProvider.getUriForFile(activity, BuildConfig.ApplicationId + ".provider", redirect);
new Handler().postDelayed(redirect::delete, 5000);
CustomTabsIntent.Builder builder = new CustomTabsIntent.Builder();
CustomTabsIntent customTabsIntent = builder.build();
customTabsIntent.intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION))
customTabsIntent.launchUrl(this, packageName, url);
} catch (IOException e) {
e.printStackTrace();
}