【问题标题】:Radio button group validation. Highlight all unchecked radiogroup buttons questions with alert Reactjs单选按钮组验证。使用警报 Reactjs 突出显示所有未选中的单选按钮问题
【发布时间】:2019-01-19 05:48:05
【问题描述】:

如何实现单选组验证

onClick 提交按钮它应该突出显示未用红色或某种验证回答的单选组或问题。

例如,如果未选择任何单选组按钮,则 onClick 提交按钮会将 ListGroupItem bsStyle="danger" 更改为特定列表。

原始代码https://stackblitz.com/edit/react-ujmlcz

//array of cards coming from the backend
const data = [
  {
    cardName: 'Do you want  sugar in your coffee',
    options: [
    { radioName: 'Yes',radioValue: '1', selected: false },
    { radioName: 'No',radioValue: '2', selected: false }]
  },
  {
    cardName: 'Do you want  milk in your coffee', 
    options: [
    { radioName: 'Yes',radioValue: '1', selected: false },
    { radioName: 'No',radioValue: '2', selected: false }]
  },
  {
    cardName: 'Do you want  low-fat-milk in your coffee', 
    options: [
    { radioName: 'Yes',radioValue: '1', selected: false },
    { radioName: 'No',radioValue: '2', selected: false }]
  }
];


class CardsList extends React.Component {
  constructor(props) {
    super(props);
    this.state = {
cards: [],

    };
  }

  componentDidMount() {
    setTimeout(() => {
      // mimic an async server call
      this.setState({ cards: data });
    }, 1000);
  }

  onInputChange = ({ target }) => {
    const { cards } = this.state;
    const nexState = cards.map(card => {
      if (card.cardName !== target.name) return card;
      return {
        ...card,
        options: card.options.map(opt => {
          const checked = opt.radioName === target.value;
          return {
            ...opt,
            selected: checked
          }
        })
      }
    });
    this.setState({ cards: nexState })
  }

  onSubmit = () => { 
  let unselectedCards = this.state.cards.filter((card) => {
   return !card.options[0].selected && !card.options[1].selected
});
    console.log("Please answer all the questions"+unselectedCards);
    
 console.log(this.state.cards.map(({ cardName, options }) => {
  const option = options.filter(({ selected }) => selected)[0]
  return ` ${option.radioValue}`
}))
  };

 onReset = () => {
        this.setState({cards:[]});
      }
  render() {
    const { cards } = this.state;
    return (
      <div>
        {
          cards.length < 1 ? "Loading..." :
            <div>
              {cards.map((card, idx) => (
                <ul>
                  {card.cardName}
                  {card.options.radioName}

                  {
                    card.options.map((lo, idx) => {
                      return <input
                        key={idx}
                        type="radio"
                        name={card.cardName}
                        value={lo.radioName}
                        checked={!!lo.selected}
                        onChange={this.onInputChange}
                      />

                    })
                  }
                </ul>
              ))
              }
              < button onClick={this.onSubmit}>Submit</button>
               < button onClick={this.onReset}>Clear</button>
            </div>
        }

      </div>
    );
  }
}

ReactDOM.render(<CardsList />, document.getElementById('root'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<div id="root"></div>

【问题讨论】:

    标签: javascript reactjs radio-button


    【解决方案1】:

    要实现这一点,您首先需要扩展您的状态模型。考虑通过添加以下内容来跟踪每张卡片中的“bsStyle”:

    const data = [
      {
        cardName: 'Tires are inflated and free of excessive wear or damage.  Nuts are tight.',
        style : 'info', // <-- this is your bsStyle tracked for each card
        options: [
          { radioName: 'Yes', radioValue: '1', selected: false },
          { radioName: 'No', radioValue: '2', selected: false }]
      },
      ...,
      ...
    ]
    

    这使您的组件能够以相同的方式了解和渲染每张卡片的适当 bsStyle。有了这个,您现在可以通过添加以下“验证”功能来更新您的 onSubmit 函数:

      onSubmit = () => {
    
        this.state.cards.forEach((card) => {
          // If no option in the card is selected, consider the card invalid
          var invalid = card.options.every(option => !option.selected)
          if(invalid) {
            card.style='danger'
          }
          else {
            card.style='info'
          }
        });
    
        // Cause form to re-render to display "danger" or "info" bsStyle
        this.setState({ cards : this.state.cards })
    
        ...
        ...
     }
    

    您还需要确保在用户更改输入时更新验证。您可以通过以下方式实现:

      onInputChange = ({ target }) => {
        const { cards } = this.state;
        const { options } = this.state;
    
        const nexState = cards.map(card => {
          if (card.cardName !== target.name) return card;
    
          const options = card.options.map(opt => {
            const checked = opt.radioName === target.value;
            return {
              ...opt,
              selected: checked
            }
          })
    
          const style = options.every(option => !option.selected) ? 'danger' : 'info'
    
          return {
            ...card,
            style,
            options 
          }
        });
        this.setState({ cards: nexState })
      }
    

    最后,您需要通过以下调整来更新ListGroupItem 的渲染方式:

    {cards.map((card, idx) => (
        <ListGroup bsStyle="custom">
            <ListGroupItem bsStyle={ card.style }>
            ...
            </ListGroupItem>
        </ListGroup>)}
    

    有关更多详细信息,您可以在此处找到完整的工作示例: https://stackblitz.com/edit/react-immp6b?file=index.js

    【讨论】:

    • 如果我在危险风格后选择答案(是或否)如何将卡片风格改回信息风格?
    • 您好,请在stackblitz.com/edit/react-immp6b?file=index.js查看更新的答案以及更新的代码示例
    • 不客气 - 看起来你取得了很大的进步 :-)
    • 对不起又给你添麻烦了。你能告诉我学习 react/javascript 的最佳资源吗?我是这个领域的新手。我应该从哪里开始。
    • 最好在一个新问题中回答这个问题 - 如果您设置了它,很高兴这样做:-)
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