【发布时间】:2018-05-21 21:00:48
【问题描述】:
我有 5 个 SQL 查询。我想在 HTML 表格中显示这些结果。现在,我已经嵌套了 while 循环来读取这些查询的结果。但是,结果表会重复前 5 列的第一行(Route 出现在所有查询中)。第 6 列是正确的。
这是我的表声明,连接数据库后的查询,以及while循环:
<table style="width:100%">
<tr>
<th>Route</th>
<th>Total Cost ($)</th>
<th>Utilization (%)</th>
<th>Number Locations Serviced</th>
<th>Total Time (Hrs)</th>
<th>Cost per Item Delivered ($)</th>
</tr>
$query1 = "SELECT RouteID as Route, ROUND(SUM(CostTo), 2) as TotalCost FROM VehicleRoutes, ContractID WHERE ContractID.ContractID >= ALL(SELECT ContractID.ContractID FROM ContractID) AND ContractID.ContractID = VehicleRoutes.ContractID GROUP BY RouteID";
$result1 = mysqli_query($conn, $query1);
$query2 = "SELECT Items.RouteID as Route, ROUND((COUNT(*)/ContractID.TruckCapacity)*100, 3) as UtilizationPercentage FROM Items, ContractID WHERE Items.ContractID = ContractID.ContractID AND Items.RouteID != 'NA' AND ContractID.ContractID >= ALL(SELECT ContractID.ContractID FROM ContractID) GROUP BY Items.RouteID";
$result2 = mysqli_query($conn, $query2);
$query3 = "SELECT V.RouteID as Route, COUNT(V.LocationIDTo) as NumLocationsServiced FROM VehicleRoutes as V, ContractID WHERE ContractID.ContractID >= ALL(SELECT ContractID.ContractID FROM ContractID) AND V.LocationIDTo != 'Warehouse' AND V.ContractID = ContractID.ContractID GROUP BY V.RouteID";
$result3 = mysqli_query($conn, $query3);
$query4 = "SELECT V.RouteID as Route, ROUND(SUM(V.TravelTime + V.DeliveryTime), 3) as TotalTime FROM VehicleRoutes as V, ContractID WHERE ContractID.ContractID >= ALL(SELECT ContractID.ContractID FROM ContractID) AND ContractID.ContractID = V.ContractID GROUP BY V.RouteID";
$result4 = mysqli_query($conn, $query4);
$query5 = "SELECT I.RouteID AS Route, ROUND(SUM(V.CostTo) / COUNT(I.ItemID) , 2) AS CostPerItemDelivered FROM Items AS I, VehicleRoutes AS V, ContractID WHERE ContractID.ContractID >= ALL(SELECT ContractID.ContractID FROM ContractID) AND I.RouteID != 'NA' AND I.RouteID = V.RouteID AND I.ContractID = ContractID.ContractID AND V.ContractID = I.ContractID GROUP BY I.RouteID";
$result5 = mysqli_query($conn, $query5);
while($col1 = mysqli_fetch_array($result1)){
while($col2 = mysqli_fetch_array($result2)){
while($col3 = mysqli_fetch_array($result3)){
while($col4 = mysqli_fetch_array($result4)){
while($col5 = mysqli_fetch_array($result5)){
echo "<tr><td>".$col1["Route"]."</td><td>".$col1["TotalCost"]."</td><td>".$col2["UtilizationPercentage"]."</td><td>".$col3["NumLocationsServiced"]."</td><td>".$col4["TotalTime"]."</td><td>".$col5["CostPerItemDelivered"]."</td></tr>";
}
}
}
}
}
【问题讨论】:
标签: mysql while-loop html-table nested-loops