PHP 输出多个 HTML 表格

Question

我对 PHP 还很陌生，想知道如何将这些信息输出到一个表中。

<?php

$url='mysite.com';
$content = simplexml_load_file($url);

foreach ($content->children() as $alarm) {

$severity = $alarm['severity'];
$id = $alarm ['id'];


echo "<table boarder=1>";
echo "<tr><th>Header1</th><th>ID</th><th>Header2</th><th>Header3</th><th>Header4</th>      <th>Header5</th></tr>";

echo "<td style=\"text-align:center\" width=100px >";
echo $severity;
echo "</td><td style=\"text-align:center\" width=100px >";
echo $id;

echo "</td><td style=\"text-align:center\" width=100px >";
echo $alarm->nodeId;
echo "</td><td style=\"text-align:center\" width=100px >";
echo $alarm->nodeLabel;

echo "</td><td style=\"text-align:center\" width=100px >";

echo $alarm->lastEventTime;
echo "</td><td style=\"text-align:center\" width=500px >";
echo  $alarm->logMessage;
echo "</td>";
echo "</table>";
}

?>

这是输出...

标题 1 标题 2 标题 3 标题 4 标题 5** $severity $id $alarm->nodeID $alarm->$nodeLabel $$alarm->logmessage 标题 1 标题 2 标题 3 标题 4 标题 5 $severity $id $alarm->nodeID $alarm->$nodeLabel $$alarm->logmessage 标题 1 标题 2 标题 3 标题 4 标题 5 $severity $id $alarm->nodeID $alarm->$nodeLabel $$alarm->logmessage

html输出如下...

<table boarder="1">...</table>
<table boarder="1">...</table>
<table boarder="1">...</table>
<table boarder="1">...</table>

我只是想要它，所以它在一张表中，标题仅在顶部。

标题 1 标题 2 标题 3 标题 4 标题 5** $severity[0] $id $alarm->nodeID $alarm->$nodeLabel $$alarm->logmessage $severity[1] $id $alarm->nodeID $alarm->$nodeLabel $$alarm->logmessage $severity[2] $id $alarm->nodeID $alarm->$nodeLabel $$alarm->logmessage

任何关于如何将这些信息全部放入一个表格或最佳实践的建议都会很棒。

Answer 1

<?php
    echo "<table boarder=1>";
    echo "<tr><th>Header1</th><th>ID</th><th>Header2</th><th>Header3</th><th>Header4</th>      <th>Header5</th></tr>";

    foreach ($content->children() as $alarm) {

        echo "<tr><td style=\"text-align:center\" width=100px >".$alarm->severity."</td><td style=\"text-align:center\" width=100px >".$alarm->id."</td><td style=\"text-align:center\" width=100px >".$alarm->nodeId."</td><td style=\"text-align:center\" width=100px >".$alarm->nodeLabel."</td><td style=\"text-align:center\" width=100px >".$alarm->lastEventTime."</td><td style=\"text-align:center\" width=500px >".$alarm->logMessage."</td></tr>";
    }

    echo "</table>";

    ?>

Answer 2

把你的

echo "<table boarder=1>";
echo "<tr><th>Header1</th><th>ID</th><th>Header2</th><th>Header3</th><th>Header4</th>      <th>Header5</th></tr>";

在您的 foreach() 条件之前，而不是在里面

Answer 3

只需打印<table boarder=1> 和foreach 循环之前的标题，然后在完成后打印出结束表标记。还可以将$content->children() 封装在表格行标签中，以便更好地衡量。

<?php

echo "<table boarder=1>";
echo "<tr><th>Header1</th><th>ID</th><th>Header2</th><th>Header3</th><th>Header4</th>      <th>Header5</th></tr>";

foreach ($content->children() as $alarm) {
    $severity = $alarm['severity'];
    $id = $alarm ['id'];

    echo "<tr><td style=\"text-align:center\" width=100px >";
    echo $severity;
    echo "</td><td style=\"text-align:center\" width=100px >";
    echo $id;

    echo "</td><td style=\"text-align:center\" width=100px >";
    echo $alarm->nodeId;
    echo "</td><td style=\"text-align:center\" width=100px >";
    echo $alarm->nodeLabel;

    echo "</td><td style=\"text-align:center\" width=100px >";

    echo $alarm->lastEventTime;
    echo "</td><td style=\"text-align:center\" width=500px >";
    echo  $alarm->logMessage;
    echo "</td></tr>";
}

echo "</table>";

?>