d3.js - 在力有向图组上添加背景矩形

Question

我想在第2组中添加一个背景矩形，想法是添加一个g元素并将所有第2组节点附加到g元素，然后使用g元素bbox绘制一个矩形。

但我不知道如何将现有节点移动到 g 元素！ （也许不可能？）。

示例代码如下：

var graph = {
  nodes:[
    {id: "A",name:'AAAA', group: 1},
    {id: "B", name:'BBBB',group: 2},
    {id: "C", name:'CCCC',group: 2},
    {id: "D", name:'DDDD',group: 2},
    {id: "E", name:'EEEE',group: 2},
    {id: "F", name:'FFFF',group: 3},
    {id: "G", name:'GGGG',group: 3},
    {id: "H", name:'HHHH',group: 3},
    {id: "I", name:'IIII',group: 3}
  ],
  links:[
    {source: "A", target: "B", value: 1},
    {source: "A", target: "C", value: 1},
    {source: "A", target: "D", value: 1},
    {source: "A", target: "E", value: 1},
    {source: "A", target: "F", value: 1},
    {source: "A", target: "G", value: 1},
    {source: "A", target: "H", value: 1},
    {source: "A", target: "I", value: 1},
  ]
};

var width = 400
var height = 200
var svg = d3.select('body').append('svg')
.attr('width',width)
.attr('height',height)
.style('border','1px solid red')

var color = d3.scaleOrdinal(d3.schemeCategory10);

var simulation = d3.forceSimulation()
.force("link", d3.forceLink().id(function(d) { return d.id; }).distance(100))
.force("charge", d3.forceManyBody())
.force("x", d3.forceX(function(d){
  if(d.group === 2){
    return width/3
  } else if (d.group === 3){
    return 2*width/3
  } else {
    return width/2 
  }
}))
.force("y", d3.forceY(height/2))
.force("center", d3.forceCenter(width / 2, height / 2));

var g = svg.append("g")
.attr("class", "nodes")
.selectAll("circle")
.data(graph.nodes)
.enter()

var w = 80
var txts = g.append('text')
.attr('class','text')
.attr('text-anchor','middle')
.attr("dominant-baseline", "central")
.attr('fill','black')
.text(d => d.name)
.each((d,i,n) => {
  var bbox = d3.select(n[i]).node().getBBox()
  var margin = 4
  bbox.x -= margin
  bbox.y -= margin
  bbox.width += 2*margin
  bbox.height += 2*margin
  if (bbox.width < w) {
    bbox.width = w
  }
  d.bbox = bbox
})

var node = g
.insert('rect','text')
.attr('stroke','black')
.attr('width', d => d.bbox.width)
.attr('height',d => d.bbox.height)
.attr("fill", function(d) { return color(d.group); })
.attr('fill-opacity',0.3)
.call(d3.drag()
      .on("start", dragstarted)
      .on("drag", dragged)
      .on("end", dragended));

var link = svg.append("g")
.attr("class", "links")
.attr('stroke','black')
.selectAll("line")
.data(graph.links)
.enter().append("path")
.attr("stroke-width", function(d) { return Math.sqrt(d.value); });

simulation
  .nodes(graph.nodes)
  .on("tick", ticked);

simulation.force("link")
  .links(graph.links);

function ticked() {
  link
    .attr("d", function(d) { 
    var ax = d.source.x
    var ay = d.source.y
    var bx = d.target.x
    var by = d.target.y
    if (bx < ax) {
      ax -= w/2
      bx += w/2
    }else{
      ax += w/2
      bx -= w/2
    }
    var path = ['M',ax,ay,'L',bx,by]
    return path.join(' ')
  })

  txts.attr('x',d => d.x)
    .attr('y',d => d.y)

  node
    .attr("x", function(d) { return d.x - d.bbox.width/2; })
    .attr("y", function(d) { return d.y - d.bbox.height/2; });

}

function dragstarted(event,d) {
  if (!event.active) simulation.alphaTarget(0.3).restart();
  d.fx = d.x;
  d.fy = d.y;
}

function dragged(event,d) {
  d.fx = event.x;
  d.fy = event.y;
}

function dragended(event,d) {
  if (!event.active) simulation.alphaTarget(0);
  d.fx = null;
  d.fy = null;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/6.7.0/d3.min.js"></script>

Answer 1

力模拟不使用 DOM 做任何事情。它只是计算节点应该在哪里，如何渲染它们，如果你渲染它们，取决于你。因此，将一些节点放在g 中而不是其他节点不是问题。例如，我们可以为组 2 添加一个g，遍历所有节点，如果它们来自组 2，则将它们从 DOM 中分离出来，然后将它们重新附加到新的g：

var parent = d3.select("g").append("g").lower();
node.each(function(d) {
    if (d.group == 2) {
      d3.select(this).remove();
      parent.append((d)=>this);      
    }
  })

那么我们需要做的就是创建一个背景矩形：

var background = d3.select("g")
  .append("rect")
  .lower()  // so it is behind the nodes.
  ....

并在勾选时使用g 的新边界框更新它，如下所示。

var graph = {
  nodes:[
    {id: "A",name:'AAAA', group: 1},
    {id: "B", name:'BBBB',group: 2},
    {id: "C", name:'CCCC',group: 2},
    {id: "D", name:'DDDD',group: 2},
    {id: "E", name:'EEEE',group: 2},
    {id: "F", name:'FFFF',group: 3},
    {id: "G", name:'GGGG',group: 3},
    {id: "H", name:'HHHH',group: 3},
    {id: "I", name:'IIII',group: 3}
  ],
  links:[
    {source: "A", target: "B", value: 1},
    {source: "A", target: "C", value: 1},
    {source: "A", target: "D", value: 1},
    {source: "A", target: "E", value: 1},
    {source: "A", target: "F", value: 1},
    {source: "A", target: "G", value: 1},
    {source: "A", target: "H", value: 1},
    {source: "A", target: "I", value: 1},
  ]
};

var width = 400
var height = 200
var svg = d3.select('body').append('svg')
.attr('width',width)
.attr('height',height)
.style('border','1px solid red')

var color = d3.scaleOrdinal(d3.schemeCategory10);

var simulation = d3.forceSimulation()
.force("link", d3.forceLink().id(function(d) { return d.id; }).distance(100))
.force("charge", d3.forceManyBody())
.force("x", d3.forceX(function(d){
  if(d.group === 2){
    return width/3
  } else if (d.group === 3){
    return 2*width/3
  } else {
    return width/2 
  }
}))
.force("y", d3.forceY(height/2))
.force("center", d3.forceCenter(width / 2, height / 2));

var g = svg.append("g")
.attr("class", "nodes")
.selectAll("circle")
.data(graph.nodes)
.enter()

var w = 80
var txts = g.append('text')
.attr('class','text')
.attr('text-anchor','middle')
.attr("dominant-baseline", "central")
.attr('fill','black')
.text(d => d.name)
.each((d,i,n) => {
  var bbox = d3.select(n[i]).node().getBBox()
  var margin = 4
  bbox.x -= margin
  bbox.y -= margin
  bbox.width += 2*margin
  bbox.height += 2*margin
  if (bbox.width < w) {
    bbox.width = w
  }
  d.bbox = bbox
})

var node = g
.insert('rect','text')
.attr('stroke','black')
.attr('width', d => d.bbox.width)
.attr('height',d => d.bbox.height)
.attr("fill", function(d) { return color(d.group); })
.attr('fill-opacity',0.3)
.call(d3.drag()
      .on("start", dragstarted)
      .on("drag", dragged)
      .on("end", dragended));

// Start Changes 1/2
var parent = d3.select("g").append("g").lower();
node.each(function(d) {
    if (d.group == 2) {
      d3.select(this).remove();
      parent.append((d)=>this);      
    }
  })
var background = d3.select("g")
  .append("rect")
  .lower()
  .attr("ry", 5)
  .attr("rx", 5)
  .attr("fill","#ccc")
  .attr("stroke","#999")
  .attr("stroke-width", 1);
// End Changes 1/2
  
      

var link = svg.append("g")
.attr("class", "links")
.attr('stroke','black')
.selectAll("line")
.data(graph.links)
.enter().append("path")
.attr("stroke-width", function(d) { return Math.sqrt(d.value); });

simulation
  .nodes(graph.nodes)
  .on("tick", ticked);

simulation.force("link")
  .links(graph.links);

function ticked() {
  link
    .attr("d", function(d) { 
    var ax = d.source.x
    var ay = d.source.y
    var bx = d.target.x
    var by = d.target.y
    if (bx < ax) {
      ax -= w/2
      bx += w/2
    }else{
      ax += w/2
      bx -= w/2
    }
    var path = ['M',ax,ay,'L',bx,by]
    return path.join(' ')
  })

  txts.attr('x',d => d.x)
    .attr('y',d => d.y)

  node
    .attr("x", function(d) { return d.x - d.bbox.width/2; })
    .attr("y", function(d) { return d.y - d.bbox.height/2; });
    
// Start changes 2/2
var box = parent.node().getBBox() 

background.attr("width", box.width+10)
  .attr("height",box.height+10)
  .attr("x", box.x-5)
  .attr("y", box.y-5);
//End Changes 2/2

}

function dragstarted(event,d) {
  if (!event.active) simulation.alphaTarget(0.3).restart();
  d.fx = d.x;
  d.fy = d.y;
}

function dragged(event,d) {
  d.fx = event.x;
  d.fy = event.y;
}

function dragended(event,d) {
  if (!event.active) simulation.alphaTarget(0);
  d.fx = null;
  d.fy = null;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/6.7.0/d3.js"></script>

如果您想要多个组，或者有动态数据，这种方法并不理想 - 需要对连接或数据结构进行一些修改以使更规范的方法起作用 - 我可能会重新审视今晚晚些时候有一个替代方案。就目前而言，这种解决方案可能是对您现有代码的侵入性最小的解决方案。