使用复合视图显示搜索结果 ASP.NET MVC 时出错答案

【问题标题】：Error using compound view to display search results ASP.NET MVC使用复合视图显示搜索结果 ASP.NET MVC 时出错
【发布时间】：2014-03-31 15:59:58
【问题描述】：

我在我的网站中创建了一个搜索功能，用户可以在其中选择他们想要搜索的项目类型。由于搜索可以使用不同的模型，我制作了一个复合视图模型来显示数据。但是当我运行搜索时，我收到一条错误消息The model item passed into the dictionary is of type 'System.Collections.Generic.List1'[BiteWebsite.Models.Restaurant]', but this dictionary requires a model item of type 'BiteWebsite.Models.Search'.

任何帮助都会很棒

搜索功能

public ActionResult Results(string Searchby, string SearchString)
        {
                if (Searchby == "Restaurant")
                {
                    ViewData["Type"] = "Restaurant";

                    return View(db.Restaurants.Where(r => r.Name == SearchString).ToList());
                }

                else
                {
                    if (Searchby == "Cuisine")
                    {
                        var type = "Cuisine";
                        ViewData["Searchtype"] = type;
                        return View(db.Cuisines.Where(c => c.Name == SearchString).ToList());
                    }
                    else
                    {
                        if (Searchby == "User")
                        {
                            var type = "User";
                            ViewData["Searchtype"] = type;
                            return View(db.Users.Where(u => u.FirstName == SearchString).ToList());
                        }

                    }
                }

                return View(SearchString);
            }

搜索视图模型

namespace BiteWebsite.Models
{
    public class Search
    {
        public IEnumerable<BiteWebsite.Models.ApplicationUser> UserSearch { get; set; }
        public IEnumerable<BiteWebsite.Models.Restaurant> RestaurantSearch { get; set; }
        public IEnumerable<BiteWebsite.Models.Cuisine> CuisineSearch { get; set; }

        [Display (Name ="Name")]
        public string Name { get; set; }

        [Display(Name = "Cuisine")]
        public string Cuisine { get; set; }

        [Display(Name = "Street Number")]
        public string StreetNumber { get; set; }

        [Display(Name = "Street Name")]
        public string StreetName { get; set; }

        [Display(Name = "County")]
        public string County { get; set; }

        [Display(Name = "PostCode")]
        public string PostCode { get; set; }

        [Display(Name = "Contact Number")]
        public string Contactnumber { get; set; }

        [Display(Name = "Website")]
        public string Website { get; set; }

        [Display(Name = "Description")]
        public string Description { get; set; }


    }

}

结果页面

@model BiteWebsite.Models.Search

@{
    ViewBag.Title = "Results";
}
@if (ViewData["Type"] == "Restaurant")
{ 
<h2>Results</h2>

<p>
    @Html.ActionLink("Create New", "Create")
</p>
<table class="table">
    <tr>
        <th>
            @Html.DisplayNameFor(model => model.Name)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Cuisine)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.StreetNumber)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.StreetName)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.County)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.PostCode)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Contactnumber)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Website)
        </th>

        <th></th>
    </tr>

@foreach (var RestaurantSearch in Model.RestaurantSearch) {
    <tr>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.Name)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.Cuisine)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.StreetNumber)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.StreetName)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.County)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.PostCode)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.Contactnumber)
        </td>
        <td>
            @Html.DisplayFor(modelItem => RestaurantSearch.Website)
        </td>

        <td>

            @Html.ActionLink("Details", "Details", "Restaurant", new { id = RestaurantSearch.id }, null) |

        </td>
    </tr>
}


</table>
}
    else {
        if(ViewData["Type"] ==  "Cuisine")
        {<h2>Results</h2>


<table class="table">
    <tr>
        <th>
            @Html.DisplayNameFor(model => model.Name)
        </th>
        <th>
            @Html.DisplayNameFor(model => model.Description)
        </th>


        <th></th>
    </tr>

@foreach (var CuisineSearch in Model.CuisineSearch) {
    <tr>
        <td>
            @Html.DisplayFor(modelItem => CuisineSearch.Name)
        </td>
        <td>
            @Html.DisplayFor(modelItem => CuisineSearch.Description)
        </td>


        <td>

            @Html.ActionLink("Details", "Details", "Restaurant", new { id = CuisineSearch.Id }, null) |

        </td>
    </tr>

        }
    </table>
    }
}

【问题讨论】：

标签： c# html search model-view-controller asp.net-mvc-5

【解决方案1】：

你的控制器需要返回一个BiteWebsite.Models.Search类型的对象，例如你需要返回：

if (Searchby == "Restaurant")
{
    ViewData["Type"] = "Restaurant";
    return View(new Search() {
      RestaurantSearch = db.Restaurants.Where(r => r.Name == SearchString).ToList())
    });
}

并且基本上对其他搜索执行相同的操作。

【讨论】：